First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8
h = 256*8 - 16*8^2
h = 1024
Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0
t1 = 0.82s
t2 = 15.17s
time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
Answer: y=2x+2
Step-by-step explanation:
Rule as an expression: 2x+11-8
Simplify: 2x+2
Rewrite as an equation with x (input) and y (output): y=2x+2
Answer:
2.66666667
Step-by-step explanation:
i looked it up
24/40
0.6/1 minute
(0.6/1minute)x60
36 pages per hour
b is the correct answer
