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Katyanochek1 [597]
4 years ago
11

The electromagnetic waves with the shortest wavelengths and the highest frequencies are called

Mathematics
1 answer:
Norma-Jean [14]4 years ago
4 0
Radio waves I believe
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Which two shapes make up the first split of quadrilaterals on the quadrilateral hierarchy?
s2008m [1.1K]

Trapezoid and kite make up the first split of quadrilaterals on the quadrilateral hierarchy

<h3>What is a quadrilateral?</h3>

A quadrilateral is a polygon that has four sides and four angles. Types of quadrilateral are<em> square, kite, trapezoid, rectangle, rhombus </em>and so on.

A quadrilateral hierarchy is a graphical way of representing the different types of quadrilaterals.

Trapezoid and kite make up the first split of quadrilaterals on the quadrilateral hierarchy

Find out more on quadrilateral at: brainly.com/question/23935806

#SPJ1

7 0
2 years ago
HELP PLEASE!
Gwar [14]
A vertical angle includes each of the pairs of opposite angles made by two intersecting lines, so ∠EKF and ∠HKI is the answer. 
8 0
4 years ago
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The term "jet stream" is often used by weather forecasters to describe
Masteriza [31]

Answer:

daddy chill what does the man say?

Step-by-step explanation:

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7 0
3 years ago
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A gym membership at one gym costs $10 every month plus a one-time membership fee of $15, and a gym membership at another gym cos
Minchanka [31]

Answer: Let us assume that the number of months after which

the gym memberships will cost the same = x

Then

15 + 10x = 40 + 4x

10x - 4x = 40 - 15

6x = 25

x = 25/6

 = 4 1/6

So the membership fee of both the gyms will become same after 4 1/6 months. You can also consider that as after 5 months the membership fees of both the gyms will become same. I hope the procedure is not very complicated for you to understand.

Step-by-step explanation: Hope this helps!!

6 0
3 years ago
Five years back, Michael's age was 2/3 the age of James. After ten years he will be 5/6 of the age of James. What are the equati
irakobra [83]
I find it easier to start from scratch and write out the equations, then compare them with the given equations.

Let m and j represent the ages of the two boys.  Then m-5=(2/3)(j-5)
Also, in ten years:  m+10 = (5/6)j.

Let's solve this system:  Mult the first eqn by 3 to remove the fraction:
3(m-5) = 2(j-5), or 3m - 15 = 2j -10.  Next, mult. the 2nd eqn by 6 to remove the fraction:  6m+60 = 5j.

Our two equations are (at this point)      3 m - 15 = 2j - 10 and
                                                                6m  +60  = 5j

Let's mult. the first equation by -2, so as to obtain the coefficient -6 for m:

-6m + 30 = -4j + 10
 6m + 60  = 5j
---------------------------
90 = j + 10, so j = 80 (wow!)

Let's now find m:  6m + 60 = 5(80), or    6m = 400+60 = 460

Then m = 76 2/3.

We must check our solution (m = 76 2/3, j = 80):

Let's subst. these values into     m-5=(2/3)(j-5)

Does 76 2/3 - 5 = (2/3)(80) - 10/3?

Does 76 2/3 - 15/3 = 160/3 - 10/3?

Does 76 - 15 = 160 - 10    No.  So something's wrong here.

Going back to the problem statement:

<span>x-5=2/3(y-5) and x+10=5/6(y+10)  seems correct!


Mike's age 5 years ago was x-5, and james' age 5 years ago was y-5.  The multiplier (2/3) is also correct.

Mikes age 10 years from now will be x+10, and james' y+10.

The first answer set is the correct one.</span>
7 0
3 years ago
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