The little dipper is located in:

1. When two atoms with different electronegativities are bonded together, a bond dipole exists. These are displayed with an arro

Natali5045456 [20]

Answer:

In order: LOWER, HIGHER, NEGATIVE, POSITIVE, INCREASE

Explanation:

First you must consider the definition of electronegativity.

All in all, electronegativity is the ability of an atom to attract electrons to itself. For this explanation, let's just consider the groups 1, 2, 13-17, and the noble gases of the periodic table. Furthermore, let's also consider the octet rule. The octet rule says that the last orbit of an atom tends to have 8 electrons in order to be stable.

If you take an atom like Sodium (Na) and search its distribution of electrons by levels, you'll see these number in the last two orbits: 8.1

The penultimate orbit has 8 electrons and the last one has only 1. Therefore, in order to futfill the octet rule what do you think it's easier? Losing the last electron and leaving the 8 electrones of the penultimate orbit as last orbit? Or maybe taking 7 electrons for the last orbit and, hence, futfilling the octet? Well, the answer is the first case.

The more you move from group to group (i.e, rightwards in the periodic table), more electrons will have in their last orbit.

So, in order to respond your question: Yes you should display it like this:

A --> B

Consider A and B two random atoms, for which B's electronegativity is higher than A's. This arrow shows the tendency of the electron flow.

As electrons go to the more electronegative atom, the whole electronic ''cloud'' will tend to be closer to B, because this atom is more electronegative. Hence, there will be a partial (not fixed) negative charge on B rather than on A. This is due to B's high electronegativity. This means that the negative charge will spend more time on B rather than on A, this is what partial negative charge means.

The higher the electronegativity is, the higher the magnitudes of the partial charges --> Therefore, these partial charges are increased and sometimes it might lead to the chemical bond breakage.

8 0

3 years ago

Chuck has a very detailed model of the solar system where each planet is made out of granite rock. Since his little sister reall

Ilia_Sergeevich [38]

He could be blindfolded and know which was his and which was his sister's. All he would need to do is pick them both up and if they were too big then pick them up one at a time. The lumber might make it harder to tell, but this is a question about physical properties.

So there is a change in mass which for the purpose of this question should be quite different. His sister's ought to be much lighter than his. He would find it easier to pick up.

8 0

3 years ago

Read 2 more answers

What is the pH of a solution with a H+ ion of 2×10-¹²?

kap26 [50]

Answer:

11.7

Explanation:

The pH is the negative logarithm of the concentration of H+ ions. If the concentration is 2×10-¹² the the pH will be -log(2×10-¹²) which is 11.698 which can be round up to 11.7.

5 0

3 years ago

What is the mass of the solid NH4Cl formed when 75.5 g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas

Gekata [30.6K]

Answer : The volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of $NH_4Cl$ produced is, 110.7 grams.

Explanation :

The balanced chemical reaction will be:

$NH_3+HCl\rightarrow NH_4Cl$

First we have to calculate the moles of $NH_3$ and HCl

$\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}$

Molar mass of NH_3 = 17 g/mole

$\text{Moles of }NH_3=\frac{75.5g}{17g/mole}=4.44mole$

and,

$\text{Moles of }HCl=\frac{\text{Mass of }HCl}{\text{Molar mass of }HCl}$

Molar mass of HCl = 36.5 g/mole

$\text{Moles of }HCl=\frac{75.5g}{36.5g/mole}=2.07mole$

Now we have to calculate the limiting and excess reagent.

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of $NH_3$

So, 2.07 mole of HCl react with 2.07 mole of $NH_3$

From this we conclude that, $NH_3$ is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

The remaining moles of HCl gas = 4.44 - 2.07 = 2.37 moles

Now we have to calculate the volume of the gas remaining.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of gas = 752 mmHg = 0.989 atm (1 atm = 760 mmHg)

V = Volume of gas = ?

n = number of moles of gas = 2.37 moles

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = $14.0^oC=273+14.0=287K$

Putting values in above equation, we get:

$0.989atm\times V=2.37mole\times (0.0821L.atm/mol.K)\times 287K$

V = 56.5 L

Now we have to calculate the moles of $NH_4Cl$

As, 1 mole of HCl react with 1 mole of $NH_4Cl$

So, 2.07 mole of HCl react with 2.07 mole of $NH_4Cl$

Now we have to calculate the mass of $NH_4Cl$

$\text{ Mass of }NH_4Cl=\text{ Moles of }NH_4Cl\times \text{ Molar mass of }NH_4Cl$

Molar mass of $NH_4Cl$ = 53.5 g/mole

$\text{ Mass of }NH_4Cl=(2.07moles)\times (53.5g/mole)=110.7g$

Thus, the volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of $NH_4Cl$ produced is, 110.7 grams.

3 0

3 years ago

A box of jello has a mass of 250 g. How many boxes must be bought to have 1 Kg of jello? *

zhuklara [117]

Answer:

Number of boxes = 4

Explanation:

Given:

Mass of one box of jello = 250 grams

Total quantity want to purchase = 1 kg = 1 × 1,000 gram = 1,000 grams

Find:

Number of boxes in 1,000 grams = ?

Computation:

Number of boxes = Total quantity want to purchase / Mass of one box of jello

Number of boxes = 1,000 / 250

Number of boxes = 4

Therefore, 4 boxes of jello must be purchase to get 1 kg of Jello.

8 0

3 years ago