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Oduvanchick [21]

3 years ago

5

What moves across axons?

2 answers:

rewona [7]3 years ago

8 0

The neuron maintains a resting membrane potential. ... Because potassium is in high concentration inside the neuron, there is a concentration gradient attempting to force potassium out of the cell. Similar forces will attempt to move sodium ions into the neuron. so the answer is A ions

gtnhenbr [62]3 years ago

5 0

I BELIEVE the answer is neurons.

See, the electrical impulse moving down a axon is a nerve impulse that help your body communicate to itself.

From there, I am not sure.

D, I suppose..?

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How many moles of xenon gas, Xe, would occopy 37.8L at stp

Charra [1.4K]

Answer:

The number of moles of xenon are 1.69 mol.

Explanation:

Given data:

Number of moles of xenon = ?

Volume of gas = 37.8 L

Temperature = 273 K

Pressure = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will put the values in formula.

1 atm × 37.8 L = n × 0.0821 atm.L/ mol.K ×273 K

37.8 atm.L = n × 22.413 atm.L/ mol.

n = 37.8 atm.L / 22.413 atm.L/ mol.

n = 1.69 mol

The number of moles of xenon are 1.69.

8 0

3 years ago

What is the pOH value of 0.0000877 M HCL

vredina [299]

Answer:

pOH=9.9

Explanation:

pH=-log[H+]= -log[0.0000877]

=4.06

pOH+ pH=14

pOH=14-4.06= 9.91

8 0

3 years ago

For many purposes we can treat ammonia NH3 as an ideal gas at temperatures above its boiling point of −33.°C. Suppose the temper

Keith_Richards [23]

Answer:

The new pressure will be 0.225 kPa.

Explanation:

Applying combined gas law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1\text{ and }V_1$ are initial pressure and volume at initial temperature $T_1$ .

$P_2\text{ and }V_2$ are final pressure and volume at initial temperature $T_2$ .

We are given:

$P_1=0.29 kPa\\V_1=V\\P_2=?\\V_2=V+50\% of V=1.5 V$

$T_1=-25^oC=248.15 K$

$T _2 = 16^oC=289.15 K$

Putting values in above equation, we get:

$\frac{0.29 kPa\times V}{248.15 K}=\frac{P_2\times 1.5V}{289.15 K}$

$P_1=0.225 kPa$

Hence, the new pressure will be 0.225 kPa.

4 0

3 years ago

Pick the answer that correctly spells a layer of the atmosphere.

Elena L [17]

I think is D A have a nice day
Good luck bye

8 0

2 years ago

A boy pushes on a wagon so that it accelerates at a rate of 0.50 m/s 2 . The wagon has a mass of 24 kg. What is the magnitude of

deff fn [24]

The answer is 12 N. I hope this helps.

6 0

3 years ago

Read 2 more answers