Write an balance the equation
Na2O + H2O -> 2 NaOH
Calculate the molecular mass of Na2O and NaOH from the atomic mass from the periodic table.
Na = 23
O=16
H=1
Na2O = 23 * 2 + 16 = 62
NaOH = 23+16+1= 40
For the stoichiometry of the reaction one mole of Na2O = 62g produce two mol of NaOH = 2* 40= 80 g
120 g Na2O x 80g NaOH / 62g Na2O=
154.8 g NaOH
Answer:
because they emit liquid waste wich is later dumped into the ocean causing a lot of harm and many fatalities in sea life
Explanation:
Answer is: the solubility of silver oxalate is <span>a. 1.4 × 10-4 m.
</span>
<span>Chemical reaction
(dissociation) of silver oxalate in water:
Ag</span>₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻<span>(aq).
Ksp(Ag</span>₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻<span>].
[C</span>₂O₄²⁻] = x; solubility of oxalate ion.
[Ag⁺] = 2[C₂O₄²⁻<span>] = 2x
1.0·10</span>⁻¹¹ = (2x)² · x = 4x³.
x = ∛1.0·10⁻¹¹ ÷ 4.
x = 1.4·10⁻⁴ M.
The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.
<h3>Oxidation and reduction</h3>
Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.
In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in while that of C in CO changed from +2 to +4 in .
Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.
More on oxidation and reduction can be found here: brainly.com/question/13699873
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