A (n + y) = 10y + 32
(an + ay) = 10y + 32
an + ay = 32 + 10y
Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y)
- 32 + an + ay + (-10y) = 10y + (-10y)
</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0
Thi could not be determined. (no solution)</span>
Answer:
<h2>The segment FE is a tangent of the sphere.</h2>
Step-by-step explanation:
Obseve the sphere in the image attached.
Notice that point A is the center of the sphere. GD is the diameter, which means AG and AD are radius.
On the other hand, remember that a tangent is a line that intersects the figure at only one point, otherwise, it would be a secant.
Therefore, segment BC is a secant and segment FE is tangent.
So, the right answer is segment FE.
Answer:
Infinite
Step-by-step explanation:
I hope this helps, if it doesn't then just message me and ill be more than happy to help :)
whelp the answer to your question, the one you put up at least is 16.333 going on infinitely or 16 and 1/3
