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Juliette [100K]
3 years ago
9

How do i solve a quadratic equation like this

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0

Answer:

D{–7, 7}

Dtep-by-step explanation:

3n² = 147

n² = 147/3

n² = 49

n = 7, -7

Ostrovityanka [42]3 years ago
5 0

Answer:

Option D. {–7, 7}

Step-by-step explanation:

3n^2 = 147

First, divide both side 3

n^2 = 147/3

n^2 = 49

Next, rearrange the variables to one side of the equation as shown below:

n^2 — 49 = 0

n^2 — 7^2 = 0

The above is now difference of two squares. This can be solve by doing the following:

(n — 7)(n + 7) = 0

n — 7 = 0 or n + 7 = 0

n = 7 or n = —7

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Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
3 years ago
Geometry
VMariaS [17]

A point P on the line segment GK may be parametrically represented as

P = (1-t)G + tK

t is a real parameter which controls where on the segment P is.  t=0 means P=G, t=1 means P=K.  We're interested in the t that gives a 3:2 ratio for PG:PK.  That's closer to K so t>1/2.   t=3/(3+2) = 3/5.

P=(1-3/5)(1,2) + (3/5)(8,12) = (2/5,4/5)+(24/5,36/5)=(26/5,40/5)=(26/5,8)

Answer: (26/5, 8)


3 0
3 years ago
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I need help please!!!!?
evablogger [386]

The answer would be n<4 because 4 is greater than n.

7 0
3 years ago
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A rhombus is ___ a parallelogram
pychu [463]

Answer:

yes

Step-by-step explanation:

4 0
4 years ago
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437,000 in Scientific notation
Serjik [45]

Answer:

4.37 X 10^5

Step-by-step explanation:

Move the decimals to the right until the number is between 1 and 10.  The number of spaces the decimal is moved is the exponent

4 0
3 years ago
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