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3 years ago

What is 8 and 2/7 + 3 and 1/3

Mathematics

1 answer:

kifflom [539]3 years ago

5 0

8and2/7+3and 1/3=>(8*7+5)/7+(3*3+1)/3=>61/7+4/3=>183/21+28/21=>211/21.

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Which pair of angles must be congruent?

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The answer is: [D]: vertical angles.
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Let f(x) = x and g(x) = 7x<br> Find fg()

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3 years ago

The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 3 se

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The school took in $52 on there second day by selling 3 senior citizen tickets and 2 child tickets. Find the price of a senior citizen

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2 years ago

Please help!! The slope of the line passing through the points (-3, 4) and (4, -1) is ___.

oksano4ka [1.4K]

I hope this helps you

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2 years ago

83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi

arlik [135]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

Step-by-step explanation:

Information given

$\bar X=32.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom given by:

$df=n-1=8-1=7$

The confidence level is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

$\chi^2_{\alpha/2}=104.139$

$\chi^2_{1- \alpha/2}=62.132$

The confidence interval is given by:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

5 0

3 years ago