X could be the positive integers 2, 3, 4, or 5
Um I can't answer without an image
Yes, it’s true, because it’s more than 3, but less than 4
Answer:
solution given:
B.
CE=2×2=4[base side is double to the line of mid point]
AB=15/2=7.5[b is a mid point]
m<AEC=75°[ corresponding angle]
5.
given:
BD=x+1
CE=x+10
we have
2BD=CE
2(x+1)=x+10
2x+2=x+10
2x-x=10-2
x=8
ok so first we would do the function d(x) = 3(8)+2
which when solved turns out to be 26
we would then do the function h(x) = 2(26) +7
which when solved turns out to be 59
so he would need 59 dollars for the donuts
