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mars1129 [50]
3 years ago
11

Solve this quadratic equation using the quadratic formula. (3 - y)(y + 4) = 3y - 5

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0
-y^2-4y+3y+12=3y-5
-y^2-4y+17=0
b^2-4ac=(-4)^2-4*(-1)*17=16+68=84
y=(4 plus or minus 2√21)/(-2)= -2 plus or minus √21
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