What is the right triangle definition of the sine function

2 answers:

8 0

Answer: Choice B. Opposite/hypotenuse

The "opposite" refers to the leg that is furthest from the reference angle. The hypotenuse is always the longest side. The longest side is directly across from the 90 degree angle.

vovikov84 [41]3 years ago

4 0

Answer:

B. Opposite/hypotenuse

Step-by-step explanation:

Remember is like SOH CAH TOA

My teacher taught it to us like this:

SOH: Sine Opposiye/hypotenuse

CAH: Adjacent/hypotenuse

TOA: Opposite/adjacent

You might be interested in

Six times the difference of a number and 4 is no more than 10.

sveta [45]

Answer: x = 17/3 or 5 2/3

Step-by-step explanation:

Let the number be x

ATQ

6(x -4) = 10

6x-24 = 10

6x = 10+24

6x = 34

x = 34/6

x = 17/3

please click thanks and mark brainliest if you like :)

4 0

3 years ago

The maximum speed of China’s CRH380A train is 4.873 × 102

Brrunno [24]

Answer:

The maglev train can reach a top speed of 431 km/h (268 mph).

Step-by-step explanation

7 0

3 years ago

1/2x + 1/3y = 7

pashok25 [27]

let's multiply both sides in each equation by the LCD of all fractions in it, thus doing away with the denominator.

$\begin{cases} \cfrac{1}{2}x+\cfrac{1}{3}y&=7\\\\ \cfrac{1}{4}x+\cfrac{2}{3}y&=6 \end{cases}\implies \begin{cases} \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{6}}{6\left( \cfrac{1}{2}x+\cfrac{1}{3}y \right)=6(7)}\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{1}{4}x+\cfrac{2}{3}y\right)=12(6)} \end{cases}\implies \begin{cases} 3x+2y=42\\ 3x+8y=72 \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{using elimination}}{ \begin{array}{llll} 3x+2y=42&\times -1\implies &\begin{matrix} -3x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-2y=&-42\\ 3x+8y-72 &&~~\begin{matrix} 3x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+8y=&72\\ \cline{3-4}\\ &&~\hfill 6y=&30 \end{array}} \\\\\\ y=\cfrac{30}{6}\implies \blacktriangleright y=5 \blacktriangleleft \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{substituting \underline{y} on the 1st equation}~\hfill }{3x+2(5)=42\implies 3x+10=42}\implies 3x=32 \\\\\\ x=\cfrac{32}{3}\implies \blacktriangleright x=10\frac{2}{3} \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \left(10\frac{2}{3}~~,~~5 \right)~\hfill$