First represent your 3 consecutive integers as follows.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
<em />
Since their sum is 84, our equation reads x + (x + 1) + (x + 2) = 84.
Simplifying on the left side we get 3x + 3 = 84.
Now subtract 3 from both sides to get 3x = 81.
Dividing both sides by 3, we find that <em>x = 27</em>.
Finally, make sure you list all your answers.
If <em>x </em>is 27 then <em>x </em>+ 1 is 28 and <em>x </em>+ 2 is 29.
Tyler concludes that 5x² will always have a larger output for the same value of x.
<u>Look at the graph below and the table given</u>
Take a random value: x = 0
Here, 1 > 0, making 2^x > 5x²
Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.
Disagree with Tyler's point.
B is the correct answer i think
Answer:
X Y
6. : 3
8. : 4
Step-by-step explanation: