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raketka [301]
2 years ago
12

Use parentheses

Mathematics
1 answer:
kolezko [41]2 years ago
6 0

Answer:

the 10 dozen equals 120

the 30 half dozen 180

120+180=300 bagels

300 bagels is your answer

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17/3 divided by 2/3 help please!:))
ludmilkaskok [199]

Answer:

0.94444444444

8 0
2 years ago
You went shopping and bought a bunch of snacks. You brought 3 bags of cheetos, 2 boxes of fruity pebbles, 4 bags of chocolate an
Elenna [48]

Answer:

4/10

Step-by-step explanation:

There are 10 items and 4 chocolates, therefore it is 4/10

5 0
3 years ago
Equations in the Form y = ax^2
ra1l [238]

Answer:

2

Step-by-step explanation:

It's 2 because 4^2 is 8 and 1^2 is 2 so that's how I got my answer

8 0
2 years ago
Help me my shawtys<br> 6 − x = −12
galben [10]

Answer:

D.18

Step-by-step explanation:

6-x=-12

-x=-12-6

-x=-18   divide both sides by -1

x=18

3 0
2 years ago
1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
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