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lisov135 [29]
3 years ago
11

When evaluating a survey, Jody saw that 54% of the respondents think that the minimum age of those awarded a driver's license sh

ould be raised, while 46% think it should remain the same. The margin of error was ±5%. Which statement is true?
Mathematics
1 answer:
Kay [80]3 years ago
5 0
May be less should be choice "C"
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It took 35 seconds for 5 songs to download to Rebecca’s computer. The next day, it took 42 seconds for 6 songs to download. Writ
sleet_krkn [62]

The equation in point-slope form to represent the time y it took to download x songs is; (y - 35) = 7(x - 5)

  • Since it took 35 seconds for 5 songs to download

  • and it took 42 seconds for 6 songs to download

In essence, we can represent the information as;

  • (5, 35) and (6,42)

To find the slope of the equation; we have;

  • Slope, m = (42-35)/(6-5)

  • m = 7

In essence, the equation in point-slope form to represent the time y it took to download x songs is;

  • (y - 35) = 7(x - 5)

Read more:

brainly.com/question/6497976

3 0
2 years ago
Square of a standard normal: Warmup 1.0 point possible (graded, results hidden) What is the mean ????[????2] and variance ??????
LenaWriter [7]

Answer:

E[X^2]= \frac{2!}{2^1 1!}= 1

Var(X^2)= 3-(1)^2 =2

Step-by-step explanation:

For this case we can use the moment generating function for the normal model given by:

\phi(t) = E[e^{tX}]

And this function is very useful when the distribution analyzed have exponentials and we can write the generating moment function can be write like this:

\phi(t) = C \int_{R} e^{tx} e^{-\frac{x^2}{2}} dx = C \int_R e^{-\frac{x^2}{2} +tx} dx = e^{\frac{t^2}{2}} C \int_R e^{-\frac{(x-t)^2}{2}}dx

And we have that the moment generating function can be write like this:

\phi(t) = e^{\frac{t^2}{2}

And we can write this as an infinite series like this:

\phi(t)= 1 +(\frac{t^2}{2})+\frac{1}{2} (\frac{t^2}{2})^2 +....+\frac{1}{k!}(\frac{t^2}{2})^k+ ...

And since this series converges absolutely for all the possible values of tX as converges the series e^2, we can use this to write this expression:

E[e^{tX}]= E[1+ tX +\frac{1}{2} (tX)^2 +....+\frac{1}{n!}(tX)^n +....]

E[e^{tX}]= 1+ E[X]t +\frac{1}{2}E[X^2]t^2 +....+\frac{1}{n1}E[X^n] t^n+...

and we can use the property that the convergent power series can be equal only if they are equal term by term and then we have:

\frac{1}{(2k)!} E[X^{2k}] t^{2k}=\frac{1}{k!} (\frac{t^2}{2})^k =\frac{1}{2^k k!} t^{2k}

And then we have this:

E[X^{2k}]=\frac{(2k)!}{2^k k!}, k=0,1,2,...

And then we can find the E[X^2]

E[X^2]= \frac{2!}{2^1 1!}= 1

And we can find the variance like this :

Var(X^2) = E[X^4]-[E(X^2)]^2

And first we find:

E[X^4]= \frac{4!}{2^2 2!}= 3

And then the variance is given by:

Var(X^2)= 3-(1)^2 =2

7 0
3 years ago
Ax + 4y = 5z, for a​
Stolb23 [73]

Answer:A=5z-4y/x

Step-by-step explanation:

You must bring 4y over first making it negative then to separate the x from the A you have to divide

4 0
2 years ago
Read 2 more answers
Solve the equation x-4/2=10
hodyreva [135]
X-4/2 = 10

x+-2=10

x-2=10

x-2+2=10+2

x=12
4 0
3 years ago
Read 2 more answers
Help please !!!!!
tatuchka [14]
*triple phytagoras*
first triangle h = second triangle h = 24 in

x = 7 (triple phytagoras)
6 0
2 years ago
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