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Ede4ka [16]
3 years ago
5

Find the size of unknown angles

Mathematics
1 answer:
Luden [163]3 years ago
4 0

Answer:

ok in this diagram we have two triangles the first triangle all angles are unknown the second triangle we have the values of two angles so we will start with the second triangle and as you know angles in a triangle add up to 180° so we will take 35 degrees + 30 degrees and name the unknown angle x is equals to 180 degrees so it will be 65 degrees + x is equals to 180° put the like terms together x will be equal to 180 degrees - 65 degrees it becomes a minus because when a plus crosses the equal sign it becomes - so x is equals to 115° and as you can see in the diagram 115° is vertically opposite z then you can extend the lines so as to understand the diagram better when you extend the lines you find that 35 degrees is equal to angle v so it will be 115 degrees + 35 degrees + x is equals to 180 degrees so 150° + x is equals to 180 degrees put the like times together x is equals to 180 degrees minus 150° x is equals to 30 degrees

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Answer:

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Step-by-step explanation:

Parallel lines have the same slope.

Changing the constant in a linear equation like this only changes the y-intercept. It has no effect on the slope of the line. So, we can change the constant from 4 to 0 and we will have a line with the same slope, parallel to the original, but with a different y-intercept.

The "standard form" of the equation of a line has the leading coefficient positive. We can make that be the case by using the multiplication property of equality, multiplying both sides of the equation by -1.

Parallel line:

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In standard form:

  3x -7y = 0

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3 years ago
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makvit [3.9K]

a. (f+g)(x) = 8x+2

b. (f-g)(x) = 4x-6

Step-by-step explanation:

Given

f(x) = 6x-2\\and\\g(x)=2x+4

<u>a. (f+g)(x)</u>

(f+g)(x)=f(x)+g(x)\\=6x-2+(2x+4)\\=6x-2+2x+4\\=6x+2x-2+4\\=8x+2

<u>b. (f-g)(x)</u>

(f-g)(x)=f(x)-g(x)\\=(6x-2)-(2x+4)\\=6x-2-2x-4\\=6x-2x-2-4\\=4x-6

Hence,

a. (f+g)(x) = 8x+2

b. (f-g)(x) = 4x-6

Keywords: Functions

Learn more about functions at:

  • brainly.com/question/5282516
  • brainly.com/question/5424148

#LearnwithBrainly

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So what do you need with and I will help you with it.

Step-by-step explanation:

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