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2 years ago

Solve this system of equations.

Mathematics

2 answers:

Rasek [7]2 years ago

8 0

Answer:

for the first one its: y=-3/4x+9

for the second one its: already done

Step-by-step explanation:

GarryVolchara [31]2 years ago

6 0

X=4 Y=6 (4,6)

It’s just the answer :)

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A local eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has

Mamont248 [21]

Answer:

Step-by-step explanation:

The owner of the store has determined that home delivery will be successful if the average time spent on the deliveries does not exceed 34 minutes. This is the null hypothesis. It is written as

H0 : µ ≤ 34

The alternative hypothesis would be

Ha : µ > 34

This is a right tailed test because of the greater then symbol in the alternative hypothesis. Since the p value for the test was found to be 0.0281281, if we use a significant level of 0.05, then the conclusion would be

Reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the average time spent on the deliveries does exceed 34 minutes.

4 0

3 years ago

Z - 1,092.8 = 1,200<br><br>A. z = 2,292.8<br><br>B. z= 2,193.8<br><br>C. z= 2,291.2

OleMash [197]

Answer:

A. z = 2292.8 is your answer

Step-by-step explanation:

Isolate the variable (z). Note the equal sign, what you do to one side, you do to the other. Add 1092.8 to both sides

z - 1092.8 (+1092.8) = 1200 (+1092.8)

z = 1200 + 1092.8

z = 2292.8

A. z = 2292.8 is your answer

3 0

3 years ago

Printed Pages in Color Time (min), x 2 6 8 18 Number of pages, y 3 9 12 27 What is the constant of variation?

aksik [14]

Answer:

3/2

Step-by-step explanation:

formula k = y/x

comes from

y = kx

k = constant of variation

when y = 3 , x = 2

k = 3/2

8 0

3 years ago

21. Who is closer to Cameron? Explain.

pickupchik [31]

Problem 21

<h3>Answer: Jamie is closer</h3>

-----------------------

Explanation:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)

To find out who's closer to Cameron, we need to compute the segment lengths AC and JC. Then we pick the smaller of the two lengths.

We use the distance formula to find each length

Let's find the length of AC.

$A = (x_1,y_1) = (20,35)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from A to C} = \text{length of segment AC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-65)^2 + (35-40)^2}\\\\d = \sqrt{(-45)^2 + (-5)^2}\\\\d = \sqrt{2025 + 25}\\\\d = \sqrt{2050}\\\\d \approx 45.2769257\\\\$

The distance from Arthur to Cameron is roughly 45.2769257 units.

Let's repeat this process to find the length of segment JC

$J = (x_1,y_1) = (45,20)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from J to C} = \text{length of segment JC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(45-65)^2 + (20-40)^2}\\\\d = \sqrt{(-20)^2 + (-20)^2}\\\\d = \sqrt{400 + 400}\\\\d = \sqrt{800}\\\\d \approx 28.2842712\\\\$

Going from Jamie to Cameron is roughly 28.2842712 units

We see that segment JC is shorter than AC. Therefore, Jamie is closer to Cameron.

=================================================

Problem 22

<h3>Answer: Arthur is closest to the ball</h3>

-----------------------

Explanation:

We have these key locations:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)
B = location of the ball = (35,60)

We'll do the same thing as we did in the previous problem. This time we need to compute the following lengths:

These segments represent the distances from a given player to the ball. Like before, the goal is to pick the smallest of these segments to find out who is the closest to the ball.

The steps are lengthy and more or less the same compared to the previous problem (just with different numbers of course). I'll show the steps on how to get the length of segment AB. I'll skip the other set of steps because there's only so much room allowed.

$A = (x_1,y_1) = (20,35)\\\\B = (x_2,y_2) = (35,60)\\\\d = \text{Distance from A to B} = \text{length of segment AB}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-35)^2 + (35-60)^2}\\\\d = \sqrt{(-15)^2 + (-25)^2}\\\\d = \sqrt{225 + 625}\\\\d = \sqrt{850}\\\\d \approx 29.1547595\\\\$

Segment AB is roughly 29.1547595 units.

If you repeated these steps, then you should get these other two approximate segment lengths:

JB = 41.2310563

CB = 36.0555128

-------------

So in summary, we have these approximate segment lengths

AB = 29.1547595
JB = 41.2310563
CB = 36.0555128

Segment AB is the smallest of the trio, which therefore means Arthur is closest to the ball.

3 0

2 years ago

Ok last question i asked was answered by a scam bot so here i go again

Daniel [21]

Answer:

Make 7 jumps, each 0.2 units long. You end at 1.4, which is the product of 7 and 0.2.

Sorry to hear about the bot! Hope this helps!

5 0

2 years ago