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2 years ago

Solve this system of equations.

Mathematics

2 answers:

Rasek [7]2 years ago

8 0

Answer:

for the first one its: y=-3/4x+9

for the second one its: already done

Step-by-step explanation:

GarryVolchara [31]2 years ago

6 0

X=4 Y=6 (4,6)

It’s just the answer :)

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Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

2 years ago

Which of the following sets of numbers could be the lengths of the sides of a triangle? A. 12 in., 24 in., 48 in.B. 12 in., 6 in

bearhunter [10]

C. And it would be a equilateral

5 0

2 years ago

Read 2 more answers

Is y-x=2x-2/3y a linear or nonlinear m?

Ivanshal [37]

Answer:

linear

Step-by-step explanation:

y - x = 2x - $\frac{2y}{3}$

$\frac{5y}{3}$ = 3x

y = 9x/5

6 0

2 years ago

Qaudriladrial ABCD had cordinates A (3, 5) B(5, 2) C(8, 4) D(6, 7) qaudriladrial ABCD is a what?

Lorico [155]

The quadrilateral is a square

<h3>What are quadrilaterals?</h3>

Quadrilaterals are polygons, that have four sides and four corners

The coordinates are given as:

A = (3, 5)
B = (5, 2)
C = (8, 4)
D = (6, 7)

Start by calculating the adjacent side lengths using:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$AB = \sqrt{(3- 5)^2 + (5- 2)^2}$

$AB = \sqrt{13}$

$BC = \sqrt{(8- 5)^2 + (4- 2)^2}$

$BC = \sqrt{13}$

The side lengths are equal.

Hence, the quadrilateral is a square