Write an equation in point slope form for the line that has a slope of 4/3 and contains the point (9,5)
1 answer:
Answer: y-5=4/3(x-9)
Step-by-step explanation:
"slope of 4/3 and contains the point (9,5)"
m=4/3, y1=5, and x1=9
Another way to do it is to put it into slope intercept form then change it to point slope form. 4x -3y -21 --> y-5=4/3(x-9)
Now you know the answer as well as the formula. Hope this helps, have a BLESSED AND WONDERFUL DAY!
- Cutiepatutie ☺❀❤
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F(x)=10-16/x
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
4∈[2,8] is the required point.
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
4∈[2,8] is the required point.