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3 years ago

Write an equation in point slope form for the line that has a slope of 4/3 and contains the point (9,5)

Mathematics

1 answer:

valkas [14]3 years ago

7 0

Answer: y-5=4/3(x-9)

Step-by-step explanation:

"slope of 4/3 and contains the point (9,5)"

m=4/3, y1=5, and x1=9

Another way to do it is to put it into slope intercept form then change it to point slope form. 4x -3y -21 --> y-5=4/3(x-9)

Now you know the answer as well as the formula. Hope this helps, have a BLESSED AND WONDERFUL DAY!

- Cutiepatutie ☺❀❤

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maxonik [38]

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3 years ago

Read 2 more answers

A parallelogram has an area of x^2 + 9x - 36. A. What are expressions for the length and width of the parallelogram?B. If x is a

katrin2010 [14]

Step-by-step explanation:

$Area \: of \: parallelogram \\ = {x}^{2} + 9x - 36 \\ = {x}^{2} + 12x - 3x - 36 \\ = x(x + 12) - 3(x + 12) \\ = (x + 12)(x - 3) \\ \implies \\ length = (x + 12) \: units \\ width = (x - 3) \: units \\$

For this parallelogram to exist least value of x should be 4.

Because if x = 3

(x - 3)= 3 - 3 =0

Thus width of parallelogram would become zero as a result area of parallelogram would become zero i. e. Parallelogram won't exist.

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3 years ago