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Yuri [45]
3 years ago
13

Which expression is equivalent to this expression? x(2x + 3)

Mathematics
1 answer:
Valentin [98]3 years ago
7 0

Use distributive property: a(b + c) = ab + ac


x(2x + 3) = (x)(2x) + (x)(3) = 2x² + 3x

You might be interested in
Factor completely 4x2 16x. 4x(x 4) x(4x 4) 4(x2 4x) Prime.
vladimir2022 [97]

Answer:

4x(x+4)

Step-by-step explanation:

With the expression 4x^{2} +16x, start by looking to see if you can take out any x-values. As you can see, both 4x^{2} and 16x have an x to the first power. You can factor that out, leaving you with the expression x(4x+16). Now you look for the largest numerical value that you can take out. Both 4 and 16 are divisible by 4, so you can factor out the number 4, leaving you with the expression 4x(x+4).

5 0
2 years ago
The local train heading for Westford at 60km/h and the express train heading for Eastford at 80 km/h pass each other at Centervi
Wewaii [24]

Answer:

The maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.

Step-by-step explanation:

Local train stats:

Rate = 60 km/h

Distance = x km

Time = x/60 hours

Express train stats:

Rate = 80 km/h

Distance = (195-x) km

Time = (195-x)/80 hours

Now we will equate both the times.

x/60 =(195-x)/80

x/3= (195-x)/4

4x= 585-3x

7x= 585

x = 83.57 km

195-x=195-83.57= 111.43 km

Hence, the maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.

3 0
3 years ago
What is the result of anding 255 and 15?
Tema [17]
The result of adding 255 and 15 is;

255 + 15 = 270


8 0
3 years ago
Simplify algerbaric fractions
avanturin [10]
What question are you asking?
5 0
3 years ago
Please help me. This is real confusing. ​
katrin2010 [14]

Answer:

1st problem: b) A=2500(1.01)^{12t}

2nd problem:  c) A=2500e^{.12t}

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

A=P(1+\frac{r}{n})^{nt}

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

A=2500(1+\frac{.12}{12})^{12t}

Time to clean up the inside of the ( ).

A=2500(1+.01)^{12t}

A=2500(1.01)^{12t}

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

A=Pe^{rt}

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

A=2500e^{.12t}.

6 0
3 years ago
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