Answer:
Step-by-step explanation:
The vertical asymptotes need to be in the denominator. They become VA's when that small expression value equals zero.
x=-2 will become (x+2)
and x=-6 will become (x+6)
The x intercepts will be in the numerator.
x=-1 will go with (x+1) and x=3 will go with (x-3)
The horizontal A must be the quotient of the coefficient of the numerator and denominator, since both the top and bottom have the same power.
To make the quotient 7, we place a seven in the numerator so 7/1=7.
P = d - 5.50
The cost of buying materials will be subtracted from what he earns. Therefore, what’s left over is the profit
No, because (2,0) is a coordinate. x=2 and y=0. So just plug in the numbers where there's x or y with the appropriate number, (2 or 0). So in the first equation, x-2y=0, when you pug in the numbers, 2-2(0)=0, you know it's wrong because 2-0=0 isn't correct. So no. the point (2,0) is not a solution to the first equation. Now plug in the numbers for the second coordinate. You get 2(2)-3(0)=1. So 4-0=1. This is once again false no no. (2,0) satisfies neither equations.
210,64,000,50 is the anwser
Answer:
Step-by-step explanation:
The expression to transform is:
![(\sqrt[6]{x^5})^7](https://tex.z-dn.net/?f=%28%5Csqrt%5B6%5D%7Bx%5E5%7D%29%5E7)
Let's work first on the inside of the parenthesis.
Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:
![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Therefore ![\sqrt[6]{a} = a^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now let's replace 
with 
which is the algebraic form we are given inside the 6th root:
![\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Bx%5E5%7D%20%3D%20%28x%5E5%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now use the property that tells us how to proceed when we have "exponent of an exponent":
Therefore we get: 
Finally remember that this expression was raised to the power 7, therefore:
^7=(x^\frac{5}{6})^7=x^\frac{35}{6}](https://tex.z-dn.net/?f=%5Btex%5D%28%5Csqrt%5B6%5D%7Bx%5E5%7D%29%5E7%3D%28x%5E%5Cfrac%7B5%7D%7B6%7D%29%5E7%3Dx%5E%5Cfrac%7B35%7D%7B6%7D)
[/tex]
An use again the property for the exponent of a exponent:
