If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
8a+3b+8a-4b=
8a+8a+3b-4b=
16a-1b=
16a-b
Hope I didn't mess up for your sake!
Answer:
10-5g >80
Step-by-step explanation:
10-5g >80
This is the statment if u want it.
Answer:
2
Step-by-step explanation:
7+2n = 11
2n = 11-7
2n = 4
n = 4/2
therefore n = 2
Given two coordinates point 1 as (-23,-14) and point 2 as(-18,2).
To find the midpoint we would use the formula below;

Where x1=-23, x2=-18, y1=-14, y2=2
We would substitute the values into the midpoint formula.

Therefore, the answer is