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3 years ago

What is the answer EXPLAIN HOW YOU GOT IT FOR BRAINLEST

Mathematics

1 answer:

Paul [167]3 years ago

5 0

Let's first see which box and whisker plots have a range of 17. The range is maximum-minimum. ( the last dot minus the first dot). For A. 20 - 4 = 16, so it can't be A. For B. 36-2 = 34, so it can't be B. For C. 36 - 19 = 17, so it could be C. And for D. 17 - 2 = 15, so it can't be D. C. must be the correct answer, but let's check if the interquartile range is 5. The IQR ( interquartile range) is the 3rd Quartile - the 1st Quartile. 33- 28 = 5. So, C. is the correct answer! Hope this helped!

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Solve the following equation by combining like terms: x+x+2+3x-6= 31 X=

Vesnalui [34]

Answer:

X= 7

Step-by-step explanation:

x+x+2+3x-6=31 Combine x's

2x+2+3x-6=31 Continue to combine x's

5x+2-6=31 Combine whole numbers

5x-4=31 Add 4 to both sides

5x=35 Divide by 5

x=7

4 0

2 years ago

Solve for x -5(x+1)+3x-3=-14

ASHA 777 [7]

Answer:

x= 3

Step-by-step explanation:

Hope I get brainliest!

6 0

2 years ago

A(9,2) B(1,6) if (2,k) is equidistant from A and B, find the value of k.

Pani-rosa [81]

P is the point (2,k)
PA = PB
PA = √(49 + (2-k)²) and PB = √(1 + (6 - k)²)
√(49 + (2-k)²) = √(1 + (6 - k)²) => (49 + (2-k)² = (1 + (6 - k)²
=> 49 + 4 - 4k + k² = 1 + 36 - 12k + k² => 8k = 37 - 53 = -16 => k = -2

5 0

3 years ago

Please help me i need it :)

Musya8 [376]

Answer:

I think the incenter of LO is 27 like ML

Step-by-step explanation:

because LO is almost the same of ML

5 0

2 years ago

Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

The question is incomplete:

"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$

8 0

3 years ago