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anzhelika [568]
2 years ago
13

Please help me Find the values of x and y

Mathematics
1 answer:
MaRussiya [10]2 years ago
5 0

(12x +15)°=75° .…(शिर्षभिमुख कोण भएर)

or, 12x+15=75

or, 12x=75-15

or, 12x=60

or, x=60÷12

or, x=5

(6y-27)°=105° .…(शिर्षभिमुख कोण भएर)

or, 6y-27=105

or, 6y=105+27

or, 6y=132

or, y=132÷6

or, y=22

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What is the measure of x in the figure below?
vlada-n [284]

Answer:

115 degree

Step-by-step explanation:

x + 65 = 180 (Sum of angles in a straight line = 180 [Also known as Linear pair])

x = 180 - 65

x = 115 degree

8 0
3 years ago
Paula Purchaser borrowed $500 at 12 percent for one year. She paid a $25 processing fee. The interest paid will be $ . Thus, the
kiruha [24]
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I need help with 4ourth grade math lesson 8 homework helper asap math
Dmitriy789 [7]

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Step-by-step explanation:

3 0
3 years ago
The total weight for a family of 4 hippos is 14,007 pounds. The mother hippo
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5 0
4 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
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