The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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In this number 1500,000,
1 is at million place and 5 is at hundred thousand place
So, the value of 1 = 1 (1,000,000) = 1 million
And the value of 5 = 5 (100,000 ) = 500,000 = Five hundred thousand
In the second number 100,500
1 is at hundred thousand place and 5 is at hundred place
The value of 1 = 1 (100,000) = 100,000 = Hundred thousand
And the value of 5 = 5 (100 ) = 500 = Five hundred
Since the digits 1 and 5 both are at different places in both the numbers so 1,500,000 and 100,500 are not the same.
Answer: 0.3125.
Step-by-step explanation:
- The chance of having a boy is 0.5,
- the chance of having a girl is also 0.5.
<u>Outcome 1: all boys</u>
boy boy boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 2: first child is a girl, all others are boys</u>
girl boy boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 3: second child is a girl, all others are boys</u>
boy girl boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 4: third child is a girl, all others are boys</u>
boy boy girl boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 5: fourth child is a girl, all others are boys</u>
boy boy boy girl
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
Therefore,
0.0625 + 0.0625 + 0.0625 + 0.0625 + 0.0625 = 0.0625 * 5 = 0.3125
Good evening ,
Answer:
<h2>•• Inner product = 3×2 + 1×8 + 4×2 = 22</h2><h2 /><h2>•• since 22 ≠ 0 then the vectors are not perpendicular.</h2>
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