Question

Someone please solve this ASAP and give answer as a square root

Answer 1

Given pyramid with a regular hexagonal base,
side length=6$\sqrt{3}$ cm
Height = 4 cm

We need to find the area of the hexagonal base.  First step is to find the apothm,
a=side*($\sqrt{3}/2$ 
=6*3/2=9
So the area of each equilateral triangle making up the base
=base*apothem/2
=6$\sqrt{3}$ *9/2
=27$\sqrt{3}$
The area of base = 6 area of each triangle
=6*27$\sqrt{3}$
=162$\sqrt{3}$

Volume of pyramid = area of base * height /3
=162$\sqrt{3}$*4/3
=216$\sqrt{3}$