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4 years ago

Someone please solve this ASAP and give answer as a square root

Mathematics

1 answer:

natima [27]4 years ago

8 0

Given pyramid with a regular hexagonal base,
side length=6 $\sqrt{3}$ cm
Height = 4 cm

We need to find the area of the hexagonal base. First step is to find the apothm,
a=side*( $\sqrt{3}/2$
=6*3/2=9
So the area of each equilateral triangle making up the base
=base*apothem/2
=6 $\sqrt{3}$ *9/2
=27 $\sqrt{3}$
The area of base = 6 area of each triangle
=6*27 $\sqrt{3}$
=162 $\sqrt{3}$

Volume of pyramid = area of base * height /3
=162 $\sqrt{3}$ *4/3
=216 $\sqrt{3}$

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“Solve each inequality and graph its solution. Show work.”

Cloud [144]

Answer:

$p$ or $p >6$

Step-by-step explanation:

Given

$|-5-p| > 11$

Required

Solve and graph

$|-5-p| > 11$

Remove absolute bracket

$-5 - p > 11$ or $-5- p$

Solve for p

$-p > 11 + 5$ or $-p < -11 + 5$

$-p > 16$ or $-p < -6$

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<em>See attachment for plot</em>

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3 years ago

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3 years ago

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IgorC [24]

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3 years ago

Suppose for some positive real number aa that (a^(1 /4) ⋅ a ^(1/ 2 )⋅ a ^(1/ 4) 2 = 3.

Grace [21]

Answer:

(a) $a=\frac{3}{2}$

(b) We use the property of exponent that when there is multiplication of two function then there exponent are added

Step-by-step explanation:

We have given expression

$(a^{\frac{1}{4}}a^{\frac{1}{2}}a^{\frac{1}{4}})2=3$

(a) We have to find the value of a

We know the property of exponent that when there is multiplication of two function then there is addition of exponent

So $a^{\frac{1}{4}+\frac{1}{2}+\frac{1}{4}}\times 2=3$

$2a=3$

$a=\frac{3}{2}$

(b) We use the property of exponent that when there is multiplication of two function then there exponent are added

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3 years ago

Sodas in a can are supposed to contain an average 12 oz. This particular brand has a standard deviation of 0.1 oz, with an avera

hoa [83]

Answer:

The probability is $P(X < 12) = 0.99286$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 12 \ oz$

The standard deviation is $\sigma = 0.1 \ oz$

The sample mean is $\= x = 12.1 \ oz$

The sample size is n = 6 packs

The standard error of the mean is mathematically represented as

$\sigma_{\= x } = \frac{\sigma}{\sqrt{n} }$

substituting values

$\sigma_{\= x } = \frac{0.1}{\sqrt{6} }$

$\sigma_{\= x } = 0.0408$

Given that the can’s contents follow a Normal distribution then then the probability that the mean contents of a six-pack are less than 12 oz is mathematically represented as

$P(X < 12) = P ( \frac{X - \mu }{ \sigma_{\= x }} < \frac{\= x - \mu }{ \sigma_{\= x }} )$