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Inga [223]
3 years ago
9

A package of cheese that contains 11 slices cost $2.97. How much would a package with 18 slices cost at the same price per slice

? Explain how you found your answer.
Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

$4.86

Step-by-step explanation:

we must found cost of 1 slice of cheese first.

11 slices of cheese are $2.97

1 slice of cheese is $2.97÷11

18 slices of cheese are $2.97÷11×18 = $4.86

or you can calculated 1 slice of cheese

2.97÷11 = $0.27 and 0.27×18 = $4.86

both methods are correct

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Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. Wh
a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

Let \overline{x} and \overline{y} be sample means of white and Jesse denotes are two random variables.

Given that both samples are having normally distributed.

Assume \overline{x} having with mean \mu_{1} and \overline{y} having mean \mu_{2}

Also we have given the variance is constant

A)

We can test hypothesis as

H0: \mu_{1} =  \mu_{2}H1: \mu_{1} > \mu_{2}

For this problem

Test statistic is

T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}

Where

s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}

We have given all information for samples

By calculations we get

s=2.41

T=2.52

Here test statistic is having t-distribution with df=(10+7-2)=15

So p-value is P(t15>2.52)=0.012

Here significance level is 0.05

Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.

We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.

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