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Inga [223]
3 years ago
9

A package of cheese that contains 11 slices cost $2.97. How much would a package with 18 slices cost at the same price per slice

? Explain how you found your answer.
Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

$4.86

Step-by-step explanation:

we must found cost of 1 slice of cheese first.

11 slices of cheese are $2.97

1 slice of cheese is $2.97÷11

18 slices of cheese are $2.97÷11×18 = $4.86

or you can calculated 1 slice of cheese

2.97÷11 = $0.27 and 0.27×18 = $4.86

both methods are correct

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Please help asap show work and dont put links
iren [92.7K]
Yes you just have to plug in x.

For example, f(x)=-2(-3)+4 and solve

-2*-3=6

6+4=10

F(x)=10
8 0
3 years ago
HELP !!!!! Tyler is laying carpet in a 20 by 15 square foot room. How many yards of carpet will it take for him to cover the who
koban [17]

Answer:

33.33 square yards

Step-by-step explanation:

Recall that 1 yd = 3ft.

(20 ft)(15 ft) = 300 ft^2

Converting this to square yards, we multiply the above result by

(1 yd)^2

------------

(3 ft)^2

obtaining

(300 ft^2)     (1 yd)^2

-------------- * ------------- = 33.33 square yards

        1            9 ft^ 2

3 0
3 years ago
Suppose that A A is a set containing 13 13 elements. Find the number of different subsets of A.
aivan3 [116]

Answer:

number of subsets of a set with 13 elements are: 2^{13}

Step-by-step explanation:

In order to solve this intuitively, we can start by a set with lesser elements. This will reveal a pattern that will be used to solve for the subsets of the 13 element set.

If we start with a set B. which contains only 3 elements.

B = \{1,2,3\}

how many subsets of B are there? well we can count them. [the set containing {1,2} and {2,1} are the same, arrangement doesn't matter]

B_{0} = \{\}\\B_{1a}=\{1\}\\B_{1b}=\{2\}\\B_{1c}=\{3\}\\B_{2a}=\{1,2\}\\B_{2b}=\{2,3\}\\B_{2c}=\{3,1\}\\B_{3a}=\{1,2,3\}\\

there are a total of 9 subsets here.

Similarly, if you try a with a subset with only two elements you'll find that it has a total of 4 subsets.

We can see that combinatorics is at play here.

for the set B. the number of subsets can be written as:

\text{\# of subsets of B} = ^3C_0+^3C_1+^3C_2+^3C_3\\\text{\# of subsets of B} = 1+3+3+1\\\\text{\# of subsets of B} = 8

if we try with a 2-element set:

\text{\# of subsets} = ^2C_0+^2C_1+^2C_2\\\text{\# of subsets} = 1+2+1\\\ \text{\# of subsets} = 4

We can use the same technique to find the number of subsets of the 13 element set.

But if you recognize a pattern here that this sets of combinations are actually part of the pascal triangle, the sum of each row of the triangle is 2^{the row's number}. hence.

\text{\# of subsets of B} = 2^3\\\ \text{\# of subsets of B} = 8

So finally, the subsets of a 13-element set A will be

\text{\# of subsets of A} = ^{13}C_0+^{13}C_1+^{13}C_2+^{13}C_3\cdots+^{13}C_{12}+^{13}C_{13}\\OR\\\text{\# of subsets of A} = 2^{13}\\\text{\# of subsets of A} = 8192

6 0
3 years ago
If we were to do this equation how would I solve it
s344n2d4d5 [400]

Answer:

- 6 \frac{1}{3}

Step-by-step explanation:

\frac{10}{3}  -  \frac{1}{3}  -  \frac{29}{3}  - ( -  \frac{1}{3} ) \\  \\  =  \frac{10}{3}  -  \frac{1}{3}  -  \frac{29}{3}   +   \frac{1}{3}  \\  \\ =  \frac{10}{3}   -  \frac{29}{3}  -  \frac{1}{3}  +   \frac{1}{3}  \\  \\ =  \frac{10 - 29}{3}   \\  \\  =  \frac{ - 19}{3}  \\  \\  =  - 6 \frac{1}{3}

6 0
4 years ago
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8 0
3 years ago
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