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Verizon [17]
3 years ago
13

3 1/2 - 1 1/3 x x= 1

Mathematics
1 answer:
slamgirl [31]3 years ago
6 0

Answer:

The value of x for the given expression is \frac{15}{8}

Step-by-step explanation:

Given as :

<u>The expression is written </u>

3\dfrac{1}{2} - 1\dfrac{1}{3} × x = 1

Or, 1\dfrac{1}{3} × x = 3\dfrac{1}{2} - 1

Or, \frac{(1\times 3) + 1}{3} × x = \frac{(3\times 2) + 1}{2} - 1

Or, \dfrac{4}{3} × x = \dfrac{7}{2} - 1

Or,  \dfrac{4}{3} × x = \dfrac{7-2}{2}

Or, \dfrac{4}{3} × x = \dfrac{5}{2}

∴ x = \frac{\frac{5}{2}}{\frac{4}{3}}

Or, x = \frac{5\times 3}{2\times 4}

I.e x = \frac{15}{8}

So, The value of x = \frac{15}{8}

Hence The value of x for the given expression is \frac{15}{8} Answer

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The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of
ivanzaharov [21]
<h2>Answer:</h2>

R_2  is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

=>   {R_2} = \frac{R_TR_1}{R_1 - R_T}       ---------------(ii)

From the question,

R_1 = 6Ω

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Substitute these values into equation (ii) as follows;

=> {R_2} = \frac{2*6}{6 - 2}

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R_2 = 3Ω

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