<span> 2(2x-3y=3)..................4x-6y=6..........equation 1
3(5x+2y=17)
...........15x+6y=51</span>........equation 2
adding equation 1 and equation 2;
19x=57
x=3
2x-3y=3
(2*3)-3y=3
6-3=3y
y=1
<span>12/25=x/88
12(88)=25(x)
1056=25x divide both sides by 25
x=42.24</span>
A. 2 and 8
It’s the pair of angles on the outer side of each of those two lines but on opposite of the transversal.
Answer:
The interest is $12
Step-by-step explanation:
You just put the percent in a decimal form(6%-0.06)Then you multiply 200 with 0.06. And the answer you get is the interest
Hope that helps :)
To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that

and the exponent

are divisible by index

. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is: