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tino4ka555 [31]
3 years ago
14

Which expression is equivalent to ^3√216x^27? 6x3 6x9 72x3 72x9

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0
To solve this problem you must apply the proccedure shown below:
 1. You have the following expression given in the problem above:
 \sqrt[3]{216 x^{27} }
 2. Rewriting the expression we have: 
 \sqrt[3]{6^3 x^{27} }
 3. You have that 6^3 and the exponent 27
 are divisible by index 3
. Therefore, you have:
 \sqrt[3]{216 x^{27} } =6 x^{9}
 Therefore, as you can see,
 the answer is the option, which is: 6 x^{9} 

Artyom0805 [142]3 years ago
8 0

Answer:

b

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The midpoints are the same point, so the diagonals bisect each other.

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<em>More elaboration on a proof</em>

The alternate interior angles formed by diagonals and the sides of the triangle are congruent, so the (point-to-point) triangles formed by the crossing diagonals are congruent ASA. Since the sides of those triangles are congruent, the diagonals meet at their midpoints. That is, the diagonals bisect each other.

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Answer:

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Step-by-step explanation:

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Answer:

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I need help pls step by step i will really appreciate pls also l will mark you the brainly if you did !
agasfer [191]

Answer:

1. 2

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3.8\sqrt{6}

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Step-by-step explanation:

Remember that \frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }, and \frac{a}{\sqrt{b}}=\frac{a}{\sqrt{b}}*\frac{\sqrt{b}}{\sqrt{b}}=\frac{a\sqrt{b}}{b}

1. \frac{\sqrt{48}}{\sqrt{12} }= \sqrt{\frac{48}{12} }=\sqrt{4}=2

2. \frac{15}{\sqrt{5} }=\frac{15}{\sqrt{5} }*\frac{\sqrt{5}}{\sqrt{5} }=\frac{15\sqrt{5} }{5}}=3\sqrt{5}

3. \frac{48}{\sqrt{6}}= \frac{48}{\sqrt{6}}* \frac{\sqrt{6}}{\sqrt{6}}= \frac{48\sqrt{6}}{6}=8\sqrt{6}

4. \frac{25}{\sqrt{10}}=\frac{25}{\sqrt{10}}*\frac{\sqrt{10}}{\sqrt{10}}=\frac{25\sqrt{10}}{10}=2.5\sqrt{10}

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3 years ago
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svp [43]

Step-by-step explanation:

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4 years ago
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