2 answers:
Always make sure both the equations have equal notations so 3x-y=1 and x-y=0 after the that u may use the normal simultaneous eqn and find values of x and y
Here, substitute the value of y from equation 1 into equation 2, x - y = -9 x - (3x - 1) = -9 x - 3x + 1 = -9 -2x = -9 - 1 x = -10/-2 x = 5 Now, substitute the value in 1st equation, y = 3(5) - 1 y = 15 -1 = 14In short, Your Answer would be: (5, 14) Hope this helps!
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