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3 years ago

What is 855 divided by 8

Mathematics

2 answers:

masha68 [24]3 years ago

7 0

The answer is 106.875

kykrilka [37]3 years ago

6 0

855/8 = 106.9
or if you dont want it simplified, 106.875

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Complete 5^9/5^3=5^a

Goryan [66]

Answer:

6=a

Step-by-step explanation:

5^9/5^3=5^a

We know that b^c = b^d = b^(c-d)

5^9/5^3=5^a

5^(9-3) = 5^a

5^6 = 5^a

The bases are the same so the exponents are the same

6=a

7 0

2 years ago

Read 2 more answers

Help please (place and label the following numbers on the number line. Order them as best as you can.)

svet-max [94.6K]

Answer:

least to greatest in order: -5/2(-2.5), -2.5, -2, -1.75, -1, 1.75, 9/4(2.25)

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2 years ago

How do you square a variable

77julia77 [94]

To square means to multiply something by itself. A variable is a letter such as x. So a squared variable=x×x=x^2.
I hope that helped.

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3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

In the diagram below secants PT & PU have been drawn from exterior point P such that the four arcs intercepted have the foll

fiasKO [112]

Answer:

x = 30°
RS = 30°, SR = TU = 120°, UR = 90°
∠P = 45°
∠UTS = 60°

Step-by-step explanation:

(a) If RS = x, then the sum of arcs around the circle is ...

x + 4x +4x +3x = 360°

12x = 360°

x = 30°

(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°

RS = 30°
ST = 120°
TU = 120°
UR = 90°

(c) Angle P is half the difference of arcs TU and RS:

∠P = (TU -RS)/2 = (120° -30°)/2

∠P = 45°

(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...

∠UTS = 120°/2 = 60°

4 0

3 years ago