Answer: 11/14, also known as eleven fourteenths
Step-by-step explanation:
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Given that two digit numbers are used and one digit is drawn randomly.
Sample space = {10,11,...99}
n(S) = 90
32 is only one number favorable
Hence P(32) = 1/90
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Odd numbers are exactly 45.
Hence prob (odd number) = 45/90 = 1/2
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Multiples of 5 are 10,15,.....95
There are exactly 18 numbers.
Hence P(a multiple of 5) = 18/90 =1/5
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Step-by-step explanation:
4x² - 12x + 9 = 5 → 4x² - 12x + 4 = 0 → x² - 3x + 1 = 0
∆ = b² - 4ac → ∆ = (-3)² -4(1)(1) = 9 - 4 = 5
x = (-(-3) ± √5)/2(1) = (3 ± √5)/2
x² - 3x + 1 = 0 → (x - 3/2)² - 9/4 + 1 = 0 → (x - 3/2)² = 5/4 → x - 3/2 = ±√5 / 2 → x = ½( 3 ± √5)