All categories

2 years ago

Solve my cousins hw please asapppo

Mathematics

2 answers:

ss7ja [257]2 years ago

8 0

Answer:

8.6

Step-by-step explanation:

fomenos2 years ago

7 0

Answer:

The TV weighs 8.6 more pounds than the picnic basket.

Exlpanaition:

Just subtract 11.4 lbs from 20lbs and that's your answer.

hope this helps :)

You might be interested in

A number cube has the numbers

kogti [31]

Answer:

that is based on luck u could get 5 everytime or none, depends on what roll

7 0

3 years ago

ANTONII [103]

55/100 or 11/20

Since 55% is 55/100 as a fraction. then at it's simplest form it's 11/20.

4 0

3 years ago

Read 2 more answers

PLS HELP! What are the solutions of 4x^2-8x+5=0

Shkiper50 [21]

x = -1/2 = -0.500
 x = 5/2 = 2.500

EITHER ONE WORKS

3 0

3 years ago

Read 2 more answers

What is the answer to the equation (4 x 6) - 25 + 1

Mashutka [201]

Zero because im smart

5 0

2 years ago

Read 2 more answers

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

2 years ago