Let U = {1, 2, 3, 4, 5, 6, 7}, A= {1, 3, 4, 6}, and B= {3, 5, 6}. Find the set A’ U B’
Art [367]
Answer:
Step-by-step explanation:
A'={2,5,7}
B'={1,2,4,7}
A'UB'={1,2,4,5,7}
Answer:
The hole is at (5,7)
Step-by-step explanation:
x^2 − 3x − 10
-------------------
x−5
Factor the numerator
(x-5)(x+2)
-------------------
x−5
There is a hole at x=5 since it will cancel in the numerator and the denominator
f(x) = x+2 and letting x = 5
f(5) = 5+2
The hole is at (5,7)
Answer:
Step-by-step explanation:
9514 1404 393
Answer:
A. ∠EAG and ∠BAC
Step-by-step explanation:
Vertical angles share a vertex and have opposite rays for sides.
Rays AE and AB are opposite; rays AG and AC are opposite. These are the only pairs of opposite rays in the figure, so the vertical angles must be constructed from one of the rays of the first pair and one of the rays of the second pair. ∠EAG and ∠BAC are a pair of vertical angles.
The other pair is ∠EAC and ∠BAG.
<u>1/3; 2/7; 2/9</u>
Lets find least common multiple
The least common multiple is 63
1/3 --> 21/63
2/7 --> 18/63
2/9 --> 14/63
As you can see I am correct, but I found the LCM by multiplying 1/3 by 21 to get to 63 and the numerator as well
