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2 years ago

Find the product. (3n - 1)(7n-7)

Mathematics

1 answer:

slega [8]2 years ago

6 0

Answer:

21n² - 28n + 7

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

3n(7n - 7) - 1(7n - 7) ← distribute both parenthesis

= 21n² - 21n - 7n + 7 ← collect like terms

= 21n² - 28n + 7

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xenn [34]

Answer:

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2 years ago

Jacob and Ashley run an animal shelter that houses only cats and dogs. they have 37 adult animals 21 cats and 16 dogs. A group o

Bond [772]

The most likely number of cats = 21/37 x 8 = 4.54 ≈ 5 cats
The most likely number of dogs = 16/37 x 8 = 3.46 ≈ 3 dogs

The probability of that arrangement happening = 1/8^2 = 1/64 = 0.00156

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2 years ago

Im doing this problem where I have to deal with fractions that have variables in them. here is the problem. I linked the picture

AVprozaik [17]

First you should combine n/6-5n/12
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2 years ago

How many parallelograms are in an octagonal prism?

Snezhnost [94]

Answer:

In this way, two hexagons and a parallelogram with five inner lines are obtained. Each hexagon has six edges, therefore the prism will have more than 12 edges. At first glance, it is thought that the parallelogram contains nine edges (seven vertical and two horizontal).

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2 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

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2 years ago