Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and

Question

3 years ago

15

then, without replacement, a face card? Express your answer as a fraction or a decimal number rounded to four decimal places

1 answer:

STALIN [3.7K] · Answer 1 · 2022-03-20T13:50:09+03:00

Answer:

0.0181 probability of choosing a king and then, without replacement, a face card.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of choosing a king:

There are four kings on a standard deck of 52 cards, so:

$P(A) = \frac{4}{52} = \frac{1}{13}$

Probability of choosing a face card, considering the previous card was a king.

12 face cards out of 51. So

$P(B|A) = \frac{12}{51}$

What is the probability of choosing a king and then, without replacement, a face card?

$P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181$

0.0181 probability of choosing a king and then, without replacement, a face card.