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3 years ago

9 Peter walked 8,900 feet from home to school.

2 answers:

4 0

$\bf \begin{array}{ccll} miles&feet\\ \cline{1-2} 1&5280\\ x&8900 \end{array}\implies \cfrac{1}{x}=\cfrac{5280}{8900}\implies 8900=5280x \\\\\\ \cfrac{8900}{5280}=x\implies 1.6856\approx x\implies \stackrel{\textit{rounded up}}{1.7=x}$

skelet666 [1.2K]3 years ago

3 0

Answer:

I would try 1.7

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What does 6-2p+5p-3 equal

viva [34]

Answer:

3 + 3p

Step-by-step explanation:

since there's no equal sign or no value that it shows all of that added together is equivalent to it's not really equal to anything. However if you're asking what that equation would look like if you simplified it down , then it would be 3 + 3p because you combine the like terms

4 0

2 years ago

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If you are adding two fractions that are both greater than 1/2, what must be true about the sum? Give three examples to support

anastassius [24]

Answer:

Step-by-step

The sum must be greater than 1 because

1/2 + 1/2= 2/2 or 1

3/4 + 8/4= 11/4

9/16+15/16=24/16

8/8+9/8=17/8

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3 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

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2 years ago

P=175e^-0.090times 25

zysi [14]

Here's my interpretation of your equation:

P=175e^(-0.090*25) (not P=175e^-0.090times 25 )

Then P = 175(0.105) = 18.4, or approx 18.

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2 years ago

Use FOIL method to find the product of (3x-2) and (2x+6)

Dima020 [189]

It would be 6x^2 + 14x -12

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2 years ago

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