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Brums [2.3K]
4 years ago
5

Please help me with this

Mathematics
2 answers:
Degger [83]4 years ago
7 0

Since all the sides would be scaled together, all the angles would still be similar.

The answer should be:

∠A ≅ ∠A'

∠B ~ ∠B'

Basile [38]4 years ago
4 0

Answer with explanation:

It is given that , Δ ABC is dilated to obtain Δ A'B'C'.

Dilation factor =3,because it is given that

\frac{A'B'}{AB}=\frac{B'C'}{BC}=\frac{C'A'}{CA}=3

→ When , a geometrical object is dilated, the two pre image and Image are similar, and size of image will be smaller than Pre image,if Dilation factor <1, and size of image will be Larger than Pre image,if Dilation factor >1.

So, when two triangles are similar,then

1. Corresponding sides are Proportional.

2. Corresponding Interior Angles are equal.

Correct Statement are

2.→CB~C'B'

3→.∠A ≅ ∠A'

5.→∠B~∠B'

Option 2,3 and 5.

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Answer:

x=7

Step-by-step explanation:

we have the triangle GHJ

If the segment side GH is equal to the segment JH

then

The triangle GHJ is an isosceles triangle

Remember that

An isosceles triangle has two equal interior angles and two equal sides

so

m∠G=m∠J

we have

m∠G=(7x+5)°

m∠J=(x+47)°

equate the equations

(7x+5)°=(x+47)°

Solve for x

7x-x=47-5\\6x=42\\x=7

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Step-by-step explanation:

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3 0
3 years ago
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GREYUIT [131]

We have two set of solutions , (  \frac{\sqrt{29} }{2}  ,  \frac{\sqrt{29} }{2} + 3 ) , (  -\frac{\sqrt{29} }{2} + 3 ,  -\frac{\sqrt{29} }{2} + 3).

<u>Step-by-step explanation:</u>

We have , the following equations:

y = x+3  and y = x^{2} +2x -4 . Let's substitute value of y in bottom equation:

⇒ y = x^{2} +2x -4

⇒ x+3 = x^{2} +2x -4

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Roots of quadratic equation are given by: a = 1, b= 1 , c = -7

x = \frac{\sqrt{b^{2}-4ac} }{2a}

⇒ x = \frac{\sqrt{b^{2}-4ac} }{2a}

⇒ x = \frac{\sqrt{1^{2}-4(1)(-7)} }{2(1)}

⇒ x = \frac{\sqrt{29} }{2} which is actually x = ± \frac{\sqrt{29} }{2} .

We know that y = x+3,

⇒ y = ± \frac{\sqrt{29} }{2} + 3.

We have two set of solutions , (  \frac{\sqrt{29} }{2}  ,  \frac{\sqrt{29} }{2} + 3 ) , (  -\frac{\sqrt{29} }{2} + 3 ,  -\frac{\sqrt{29} }{2} + 3).

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