3 years ago

Multiply.

Mathematics

2 answers:

mariarad [96]3 years ago

7 0

Answer:

6x^3+7x^2+2x

Step-by-step explanation:

beks73 [17]3 years ago

5 0

Answer:

D) 6x³ + 7x² + 2x

Step-by-step explanation:

2x × 3x² = 6x³

2x × 2x = 4x²

1 × 3x² = 3x²

1 × 2x = 2x

Collect like terms to get

6x³ + 7x² + 2x

Hope this helps ya!

You might be interested in

René is twice as old as Jim In four years the sum of their ages is 60 how old are they now

Brrunno [24]

R=16
J=32
20+40(which is 20×2)=60
20-4=16
16×2=32

3 0

3 years ago

Which of the following<br> is equivalent to 4/5 ?<br> Select your answers) below

kondor19780726 [428]

We need the options to help

3 0

3 years ago

Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the even

Allushta [10]

Answer:

$P(E|A)= \frac{10}{11}$

Step-by-step explanation:

Given

Two rolls of die

$E \to$ one of the outcomes is 6

$A \to$ atleast one is 6

Required

P(E|A)

First, list out the outcome of each

$E = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

So:

$P(E|A)= \frac{n(E\ n\ A)}{n(A)}$

Where:

$E\ n\ A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$n(E\ n\ A) = 10$

$n(A) = 11$

So:

$P(E|A)= \frac{10}{11}$

7 0

2 years ago

There were 442 students at Deerlake Middle School who voted on a theme for the spring

koban [17]

Answer:

581

mark me as brainliest plz

6 0

3 years ago

32 help me with all of them thanks

grigory [225]

32a) the same six numbers are reported in the same order but at different starting points

b) All have sum of 999
c) yes, it is the same. 5/13=0.384615
384+615=999

4 0

3 years ago