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podryga [215]
3 years ago
11

Add 1/4 and 5/8 by using the giant one to create a common denominator thanks

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

7/8

Step-by-step explanation:

1/4×2=2/8....2/8+5/8=7/8

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Graph ​ y−5=−23(x+9) ​ using the point and slope given in the equation. Use the line tool and select two points on the line.
jarptica [38.1K]
Maybe try (-9, 6) and (-9,5) 
i think it may be correct
7 0
3 years ago
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1. Part A: Use the properties of exponents to explain why 64^1/2 is called the square root of 64.
Dmitriy789 [7]
A: When you multiply two numbers, their exponents add. 
So, 64^{\frac{1}{2}} * 64^{\frac{1}{2}} = 64^{\frac{1}{2} + \frac{1}{2}} = 64^{1} = 64

Since 64^1/2 multiplied by itself is 64, then it is the square root of 64.

B: The area is irrational. 7 * √7 is irrational.
8 0
3 years ago
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Round 0.05 to the nearest whole
Verdich [7]
0.05 rounded to the nearest whole number is 0.
Hope this helps~
5 0
3 years ago
A runner increased her distance from 9 miles to 12.5 miles a week. Find the percent increase in mileage.
kondor19780726 [428]

Answer:

<u>39 percent</u> is increase in mileage.

Thus, the correct option is B. 39%.

Step-by-step explanation:

Given:

A runner increased her distance from 9 miles to 12.5 miles a week.

Now, to find percent increase in mileage.

Previous mileage = 9 miles.

Present mileage = 12.5 miles.

<em>Mileage increase = 12.5 - 9 = 3.5 miles.</em>

Now, to get the percent increase in mileage:

\frac{Mileage\ increased}{previous\ mileage} \times 100

=\frac{3.5}{9} \times 100

=\frac{350}{9}

=38.88\%.

<u><em>Approximately the percent increase = 39%.</em></u>

Therefore, 39% is increase in mileage.

Thus, the correct option is B. 39%.

4 0
3 years ago
What figure has a perimeter of 22 units?
Sav [38]
Without knowing the shape selection you have i cant really say anything.  But with a square you wouldnt have any whole numbers, nor would a triangle give you whole number, than again no shape that i can think of would give whole numbers.  
6 0
3 years ago
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