Question

X^2/3-3x^1/3-4=05Cfrac%7B1%7D%7B3%7D%20%7D%20%20-%204%20%3D%200" id="TexFormula1" title="{x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0" alt="{x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0" align="absmiddle" class="latex-formula">

Answer 1

${x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0$
Solve using substitution
${t}^{2} - 3t - 4 = 0$
Solve the equation
$t = 4 \\ t = - 1$
Return the substituted values
${x}^{ \frac{1}{3} } = 4 \\ {x}^{ \frac{1}{3} } = - 1$
Solve the equations
$x = 64 \\ x = - 1$
The final solutions are,
$x1 = - 1 \\ x2 = 64$