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Zigmanuir [339]
3 years ago
10

X^2/3-3x^1/3-4=0

5Cfrac%7B1%7D%7B3%7D%20%7D%20%20-%204%20%3D%200" id="TexFormula1" title="{x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0" alt="{x}^{ \frac{2}{3} } - {3x}^{ \frac{1}{3} } - 4 = 0" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

{x}^{ \frac{2}{3} }  -  {3x}^{ \frac{1}{3} }  - 4 = 0
Solve using substitution
{t}^{2}  - 3t - 4 = 0
Solve the equation
t = 4 \\ t =  - 1
Return the substituted values
{x}^{ \frac{1}{3} }  = 4 \\  {x}^{ \frac{1}{3}  } =  - 1
Solve the equations
x = 64 \\ x =  - 1
The final solutions are,
x1 =  - 1 \\ x2 = 64


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