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Salsk061 [2.6K]
3 years ago
10

X + y = 4 x - 2y = -5 If the first equation is multiplied by 2 and then the equations are added, the result is _____.

Mathematics
2 answers:
Troyanec [42]3 years ago
8 0
X + y = 4....multiplied by 2 = 2x + 2y = 8

x - 2y = -5
2x + 2y = 8
---------------add
3x = 3......u r correct <==
kobusy [5.1K]3 years ago
3 0
Yes you are correct
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PLEASE HELP ON THESE 2
marishachu [46]
The answers to these problems are 1.B and 2.C
3 0
3 years ago
Which point lies on the circle represented by the equation (x + 5)2 + (y − 9)2 = 82?
Virty [35]

Answer:

x = −y+45

Step-by-step explanation:

Step 1: Add -2y to both sides.

Step 2: Add 8 to both sides.

Step 3: Divide both sides by 2.

3 0
3 years ago
The first day of Sam's vacation was a Monday. What day of the week was the Day 36 of Sam's vacation?
makvit [3.9K]

Answer:

A. Monday

Step-by-step explanation:

The solution to this problem can be found by creating a table

If Day 1 was Monday, then

Mon    Tues      Wed      Thur    Fri      Sat      Sun

1              2           3             4        5        6          7

8             9           10           11        12       13        14

...............

We can see that the multiples of 7 are falling on Sundays so we will divide 36 by 7 to get the closest multiple of 7 to 36.

The closest multiple of 7 near 36 is 35 so Day 35th will fall on Sunday and Day 36 will be on Monday

Hence, Option A is the correct answer..

3 0
3 years ago
Pls help me!! thank you!!
klasskru [66]

Full working out shown from step 1 to last.

follow it and you get 24 square feet as final answer. Good luck in other questions!!!

3 0
3 years ago
Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
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