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grigory [225]
3 years ago
10

Need help with all this

Mathematics
1 answer:
Inessa [10]3 years ago
7 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ To find the mean, add up all the numbers and divide by the amount of numbers there are. To find the range, subtract the highest number by the  lowest number in the data set.

2. Mean = 35  Range = 78

3. Mean = 43  Range = 58

4. Mean = 63  Range = 73

5. Mean = 61   Range = 56

6. Mean = 55  Range = 83

7. Mean = 61   Range = 53

8. Mean = 60  Range = 75

9. Mean = 50  Range = 76

10. Mean = 50  Range = 81

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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8

Step-by-step explanation:

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Is 2/3 greater then1/5
Greeley [361]
Yes, it is. To find this out, you need to make the denominators the same. They can both multiply into 15, so we change the denominators to 15. Whatever we do to the bottom, we also have to do to the top.

2/3 = 10/15

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8 0
3 years ago
COSO ---
Vsevolod [243]

Answer:

• zero: -4, -4/3, 7

• positive: -4 < x < -4/3 . . . or 7 < x

• negative: x < -4 . . . or -4/3 < x < 7

Step-by-step explanation:

Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.

The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)

3 0
3 years ago
Use each model to predict the life expectancy of residents of a country for which the average annual income is $80,000
Mandarinka [93]

The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393

The life expectancies of the models are given as:

y =69.9352 + 0.1530\times (income) --- model 1

y =4.2436 + 0.0021\times (income) --- model 2

y =4.1393 + 0.0603\times (income) --- model 3

Given that the average annual income is $80,000;

We simply substitute 80000 for income in the equations of the three models.

So, we have:

<u>Model 1</u>

y =69.9352 + 0.1530\times (income)

y =69.9352 + 0.1530\times 80000

y =12309.9352

<u>Model 2</u>

y =4.2436 + 0.0021\times (income)

y =4.2436 + 0.0021\times 80000

y =172.2436

<u>Model 3</u>

y =4.1393 + 0.0603\times (income)

y =4.1393 + 0.0603\times 80000

y =4828.1393

Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393

Read more about linear models at:

brainly.com/question/8609070

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