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lorasvet [3.4K]
3 years ago
11

The cook sends all his french fries to one store. If he can pack up to 15 servings in a box for shipping what is the minimum num

ber of boxes he needs to ship all the french fries in two weeks?
Mathematics
1 answer:
Leona [35]3 years ago
5 0
What is the total number of French fries?
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Which number line shows the solutions to 1/2 x -2 > 0
Mkey [24]

Answer:

The top choice

Step-by-step explanation:

1/2 x -2 > 0

Add 2 to each side

1/2 x -2+2 > 0+2

1/2 x > 2

Multiply each side by 2

1/2 x *2 > 2*2

x > 4

There is an open circle at 4 and the line goes to the right

5 0
3 years ago
Read 2 more answers
Is the distribution a discrete probability​ distribution?
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N fknvnab;nkfanlvkbdsljnv.jrehv;iavdsirhkebnkljarwnfbnkvbw<em>n;kjnv;kjnrk</em>
3 0
3 years ago
Can somebody help me with this question please ?
inysia [295]

Answer: No.

Step-by-step explanation: g should also be factored out. 10g(a - 3z).

4 0
3 years ago
Find the EXACT value of sin(A−B) if cos A = 3/5 where A is in Quadrant IV and cos B = 12/13 where B is in Quadrant IV. Assume al
MissTica

\bf \textit{Sum and Difference Identities} \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta)

well, for both angles A and B we're on the IV Quadrant, meaning, the sine is negative, the cosine is positive, likewise, the opposite side is negative and the adjacent side for the angle is positive.

\bf cos(A)=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{5^2-3^2}}\implies b = \pm 4 \\\\\\ \stackrel{IV~Quadrant}{b = -4}\qquad \qquad sin(A)=\cfrac{\stackrel{opposite}{-4}}{\underset{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill\\\\ cos(B)=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{13}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{13^2-12^2}}\implies b = \pm 5

\bf \stackrel{IV~Quadrant}{b = -5}\qquad \qquad sin(B)=\cfrac{\stackrel{opposite}{-5}}{\underset{hypotenuse}{13}} \\\\[-0.35em] ~\dotfill\\\\ sin(A-B)=\cfrac{-4}{5}\cdot \cfrac{12}{13}-\left( \cfrac{3}{5}\cdot \cfrac{-5}{13} \right)\implies sin(A-B)=\cfrac{-48}{65} - \left( \cfrac{-15}{65} \right) \\\\\\ sin(A-B)=\cfrac{-48}{65} + \cfrac{15}{65}\implies sin(A-B)=\cfrac{-33}{65}

4 0
3 years ago
Y=2,y=-1/2 thats the equation but it told me to write more idk why
Darina [25.2K]

More information is needed.

8 0
3 years ago
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