I’m not 100% sure but I think it’s 4 for the gcf
The answer to your question is 11
Find two numbers with a sum of 20 and a difference of 14
Make two equations
X+Y=20
X-Y=14
Now add x since y cancels out and add 20+14 To end up with
2x=34
Now divide 2 both sides to get x alone
2x/2=34/2
X=17
Now substitute x answer to first equation and solve for y
17+y=20
Subtract 17 both sides
Y= 3
Your two numbers are
3 and 17
I had this question and SAS is the correct answer
Answer:
A
Step-by-step explanation:
y=4x+6
y=6-4x
y=12
y=4x+6
12=4x+6
12-6=4x
6/4=4x/4
x=3/2
