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3 years ago

What is the midpoint of FB?Point APoint GPoint HPoint L

Mathematics

2 answers:

guajiro [1.7K]3 years ago

8 0

Answer:

The answer is D. on edgen.

Step-by-step explanation:

D. point L

vazorg [7]3 years ago

7 0

Answer: The correct option is (D) point L.

Step-by-step explanation: We are given to find the mid-point of FB from the figure shown.

The point F is located on the number line at - 2,

and

the point B is located on the number line at 8.

Therefore, the mid-point of the line FB will be located at

$M_{FB}=\dfrac{-2+8}{2}\\\\\\\Rightarrow M_{FB}=\dfrac{6}{2}\\\\\\\Rightarrow M_{FB}=3.$

Since the point L is located at 3 on the number line.

So, the mid-point of FB will be the point L.

Thus, (D) is the correct option.

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maks197457 [2]

Let angle be alpha

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3 years ago

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Step-by-step explanation:

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3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

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3 years ago

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Novosadov [1.4K]

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