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3 years ago

What is the place value of the 8 in 0.829?

Mathematics

2 answers:

emmasim [6.3K]3 years ago

6 0

Answer: Tenths
The 8 is in the tenths place, the 2 is in the hundredths, and 9 in the thousandths

Oliga [24]3 years ago

5 0

The answer is tenths because that the digit right behind the decimal.

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Find the solution of the system of equations. 15x -4y = -50 3x - 2y = -16

Fittoniya [83]

Answer:

15x - 4y =-50 -----(i)

3x - 2y=-16 --------(ii)

Using Substitution

From (i)

15x=4y-50

x=4y-50/15

Substitute x=4y-50/[15] into eqn (ii)

3x - 2y= -16

3[4y-50]/15 - 2y =-16

Multiply through by 15 to clear the fraction

3(4y - 50) - 30y=-240

12y - 150 -30y=-240

12y-30y=-240+150

-18y = -90

y=90/18

y=5.

Substitute into any eqn of choice to get x

3x - 2y=-16

3x - 2(5)=-16

3x - 10=-16

3x=-16+10

3x=-6

x=-6/3

x=-2.

x= -2

y=5

5 0

3 years ago

Angles U and V are supplementary angles. The ratio of their measures is 7:13 Find the measure of each angle

GREYUIT [131]

If $u$ and $v$ are supplementary angles, then

$u+v=180^{\circ}~~~~~\mathbf{(i)}$

The ratio of $u$ and $v$ is $\dfrac{7}{13}:$ 

$\dfrac{u}{v}=\dfrac{7}{13}\\\\\\ u=\dfrac{7v}{13}~~~~\mathbf{(ii)}$

Substitute $\mathbf{(ii)}$ into $\mathbf{(i)}:$

$\dfrac{7v}{13}+v=180^{\circ}\\\\\\ \left(\dfrac{7}{13}+1 \right )\cdot v=180^{\circ}\\\\\\ \left(\dfrac{7}{13}+\dfrac{13}{13} \right )\cdot v=180^{\circ}\\\\\\ \dfrac{20}{13}\cdot v=180^{\circ}\\\\\\ v=180^{\circ}\cdot \dfrac{13}{20}\\\\\\ \boxed{\begin{array}{c} v=117^{\circ} \end{array}}$

From $\mathbf{(i)},$ we find the measure of $u:$

$u=180^{\circ}-v\\\\ u=180^{\circ}-117^{\circ}\\\\ \boxed{\begin{array}{c} u=63^{\circ} \end{array}}$

7 0

3 years ago

Solve for g. g/6 - -53 = 57

Mashcka [7]

Step-by-step explanation:

g/6 - -53 = 57

g/6 + 53 = 57

g/6 = 4

g = 4×6 = 24

5 0

2 years ago

Please help me! thank you so much

Luda [366]

The Correct Answer Is f(x)=2.5x+5

7 0

3 years ago

What is 5/6 plus 7/8?

irina [24]

Answer:

1 17/24

Step-by-step explanation:

8 0

3 years ago

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