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tankabanditka [31]
3 years ago
9

Please help ASAP 25 pts + brainliest to right/best answer

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
5 0
D is the right answer
Whitepunk [10]3 years ago
4 0
The answer seems to be D!!
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List the sides of △ABC in order from longest to shortest if the angles of △ABC have the following measures: m∠W = 4x - 1, m∠X =
Leto [7]

Answer:

w=4x

Step-by-step explanation:

5 0
3 years ago
Andrew is elder to Brian by 2 years. Andrew's father Frank is twiceas old as Andrew, and Brian is twice as old as his sister Sar
babunello [35]

Let "x" represent the age of Brian.

Andrew is elder than Brian by 2 years, we can symbolize his age as "x+2"

Frank is twice as old as Andrew, we can symbolize his age as "2(x+2)"

Sarah has half the age of Brian's, we can symbolize her age as "x/2"

Frank ans Sarah's ages differ by 40 years, we can symbolize this as:

2(x+2)-\frac{x}{2}=40

Solve the term is parenthesis

\begin{gathered} 2x+4-\frac{1}{2}x=40 \\ 2x-\frac{1}{2}x+4=40 \\ \frac{3}{2}x=40-4 \\ \frac{3}{2}x=36 \\ x=24 \end{gathered}

x=24 years

Andrew's age is

x+2=24+2=26

Andrew is 26 years old

3 0
1 year ago
Whoever answers this correctly gets brainliest
ELEN [110]

Answer: 11. Is A

Step-by-step explanation:

5 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

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3 years ago
Find the slope from the given table:<br> х Y<br> -3. 8<br> 0. 7 <br> 3. 6
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The answer is plus +3 for slope
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