]Eigenvectors are found by the equation
implying that
. We then can write:
![A-\lambda I = \left [ \begin{array}{cc} 4-\lambda & 2 \\ 5 & 1-\lambda \end{array}\right ]](https://tex.z-dn.net/?f=%20A-%5Clambda%20I%20%3D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bcc%7D%204-%5Clambda%20%26%202%20%5C%5C%205%20%26%201-%5Clambda%20%5Cend%7Barray%7D%5Cright%20%5D%20)
And:
Gives us the characteristic polynomial:
So, solving for each eigenvector subspace:
![\left [ \begin{array}{cc} 4 & 2 \\ 5 & 1 \end{array} \right ] \left [ \begin{array}{c} x \\ y \end{array} \right ] = \left [ \begin{array}{c} -x \\ -y \end{array} \right ]](https://tex.z-dn.net/?f=%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bcc%7D%204%20%26%202%20%5C%5C%205%20%26%201%20%5Cend%7Barray%7D%20%5Cright%20%5D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bc%7D%20x%20%5C%5C%20y%20%5Cend%7Barray%7D%20%5Cright%20%5D%20%3D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bc%7D%20-x%20%5C%5C%20-y%20%5Cend%7Barray%7D%20%5Cright%20%5D%20)
Gives us the system of equations:
Producing the subspace along the line
We can see then that 3 is the answer.
Answer:
404.98 m
Step-by-step explanation:
The angle of depression is 5°
The horizontal distance from the airplane to the atoll is 4629 meters.
We need to find the height of the plane.
If we consider a triangle. 4629 meters will be the base and angle is 5°. Let h is the height of the plane. Using trigonometry to find it :
So, the height of the plane is 404.98 m.
Answer:
-a(a+4)/(16 - a²)
Step-by-step explanation:
a/(a - 4) Multiply by (a + 4)/(a + 4)
= a(a + 4)/[(a – 4)(a + 4)] Multiply the denominatorator terms
= a(a + 4)/(a² - 16) Multiply by -1/(-1)
= -a(a+4)/(-a² + 16) Reorder terms in denominator
= -a(a+4)/(16 - a²)
Answer:
The answer would be -35.
Step-by-step explanation: (14-48) + (93 DIVIDED BY (-95))= -34.9789473684 WHICH ROUNDS OUT TO BE -35.
