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kirill [66]
3 years ago
6

5000 at 12% compound quarterly compared interest earned after 5 year's

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

A = P(1+r÷100)^n

where A is amount after some days

r is the rate

n is the number of years

p is the principle (the amount of money before the interest)

A = 5000 ( 1 + 12÷100)^5

A = 8811.70

A = 8812

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Answer:

<em>31° </em>

Step-by-step explanation:

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3 years ago
Rewrite the following in the form log(c).<br> log(10) - log(2)
serg [7]

Answer:

log 5

Step-by-step explanation:

We can rewrite this by using a property of logs

log a - log b = log (a/b)

log(10) - log(2)

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4 years ago
A sphere with a radius of 6cm has the same volume as a cylinder with a height of 4.5cm. What is the radius of the cylinder
yawa3891 [41]
Short answer: r = 8
Remark
The easiest way to do this is to solve the sphere's volume in terms of pi. When you do this, you can equate that to the formula for a cylinder and cancel the pi values. 

Step One
Find the volume of the sphere.

<em>Givens</em>
r = 6 cm

<em>Formula</em>
V = (4/3) pi r^3

<em>Sub and Solve</em>
V =  4/3 pi * 6^3
V = 288 * pi

Step two 
Find the radius of the cylinder

<em>Givens</em>
V = 288* pi cm^3
h = 4.5 cm

<em>Formula</em>
V = pi r^h

<em>Sub and solve</em>
288 pi cm^3 = pi r^2 * 4.5    Divide both sides by pi
288 cm^3 = 4.5 r^2              Divide both sides by 4.5
388 / 4.5 = r^2
64 = r^2                                Take the square root of both sides.
r = square root( 64)
r = 8 <<<<< Answer

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3 years ago
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I think the answer is a. -3x^2-x-5
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3 years ago
Which of the following is the sum of all the odd integers between 5 and 102?
STALIN [3.7K]

Answer:

2601

Step-by-step explanation:

The integers between 5 and 102 are

7, 9, 11, 13, 15, 17,19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99, 101

The sum of the odd intergers between 2 and 105 can be calculated as follows

= (N + 1/2)^2

= (101 + 1 /2) ^2

= (102/2)^2

= 51^2

= 2601

Hence the sum of the odd intergers between 5 and 102 is 2601

3 0
3 years ago
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