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kirill [66]
2 years ago
6

5000 at 12% compound quarterly compared interest earned after 5 year's

Mathematics
1 answer:
hichkok12 [17]2 years ago
8 0

Answer:

A = P(1+r÷100)^n

where A is amount after some days

r is the rate

n is the number of years

p is the principle (the amount of money before the interest)

A = 5000 ( 1 + 12÷100)^5

A = 8811.70

A = 8812

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A company advertises that its cans of caviar each contain 100 g of their product. A consumer advocacy group doubts this claim, a
Blizzard [7]

Answer:

The value of the test statistic is -3.14.

Step-by-step explanation:

Test statistic:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value, \sigma is the standard deviation and n is the size of the sample.

A company advertises that its cans of caviar each contain 100 g of their product.

This means that \mu = 100

They calculate a sample mean weight of 99 g and a sample standard deviation of 0.9 g. Sample of 8 cans.

This means that X = 99, \sigma = 0.9, n = 8

So the test statistic will be given by:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{99 - 100}{\frac{0.9}{\sqrt{8}}}

t = -3.14

The value of the test statistic is -3.14.

8 0
3 years ago
1. SOCCER Suppose a youth soccer field has a
padilas [110]

Answer:

L = 100

W = 60

Step-by-step explanation:

2L + 2W = 320

-2L + 2W = -80

4W = 240

W = 60

L - W = 40

L - 60 = 40

L = 100

6 0
2 years ago
When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
What is the area of a circle with endpoints (-2, 0), (0, 2), (0, -2), and (2, 0).
Nataly_w [17]
I hope this helps you

4 0
2 years ago
Read 2 more answers
Last year Marta invested money in two accounts. The first account had an interest rate of 3% and the second account had an inter
KatRina [158]

The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.

<h3>How do we calculate the amount invested?</h3>

Let x represents the amount invested in the first account.

Therefore, we have:

Amount invested in the second account = x - 500

Interest income from first account = 3% * x = 0.03x

Interest income from second account = 5% * (x - 500) = 0.05x - 25

Total interest income = 0.03x + 0.05x - 25 = 719

Solving for x, we have:

0.08x = 719 + 25

x = 744 / 0.08

x = $9,300

Substituting for x, we have:

Amount invested in the second account = $9,300 - $500 = $8,800

Learn more about the amount invested here: brainly.com/question/24132106.

#SPJ1

3 0
1 year ago
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