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Ket [755]
3 years ago
12

CAN SOMEONE PLEASE HELP ME!! I NEED HELP WITH 6TH GRADE MATH!!!

Mathematics
2 answers:
balu736 [363]3 years ago
5 0
That's the correct answer :) Good job!
Ksju [112]3 years ago
4 0
Yes! It is correct! Good Job!
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How to add one digit number to 19. Write a sentence to explain
Liula [17]
You can add 9.5 plus 9.5 and get 19.
3 0
3 years ago
Please subscribe to my friend's channel, his name is Robertortil, it is in Spanish but subscribe and give many likes
serg [7]

Answer: ok?

Step-by-step explanation:

5 0
3 years ago
A jar contains black and white marbles in the ratio 2:5. If the jar contains total of 35 marbles, how many of the marbles are bl
Svet_ta [14]

Answer:

10 black marbles

Step-by-step explanation:

Let black marbles be=2x

Then white marbles=5x

Total marbles=7x which in turn is equal to 35. Hence x=5

Black marbles=2*5=10

H2H

8 0
3 years ago
A surveyer wants to find the distance from points A and B and to an inaccessible point C. These three points form a triangle. Be
Vinil7 [7]

Answer:

42.8°

Step-by-step explanation:

The sine rule states that for a triangle with lengths of a, b and c and the corresponding angles which are opposite the sides as A, B and C, then the following rule holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}  =\frac{c}{sin(C)}

Given that points A, B and C forms a triangle with angle A = 65°, distance from A-to-C = 90 m and the distance from B to C = 120 m.

The distance from A to C is the side opposite to angle B. Hence let b =  distance from A to C = 90 m.

The distance from B to C is the side opposite to angle A. Hence let a =  distance from B to C = 120 m.

Therefore using sine rule:

\frac{a}{sin(A)}=\frac{b}{sin(B)}  \\\\\frac{120}{sin(65)}=\frac{90}{sin(B)}  \\\\sin(B)=\frac{90*sin(65)}{120} \\\\sin(B) =0.6797\\\\B=sin^{-1}(0.6797)\\\\B=42.8^o

7 0
2 years ago
Can someone help me with these math problems please? I need it done by tonight if someone can please help me by then...I'll make
kotegsom [21]

Answer:

For question 3, you would just add 2 to the x values and subtract 2 from the y values, so it would be:

J' (-2, 5)

K' (2, 6)

L' (1, 2)

M' (-3, 1)

For question 4 you would subtract 7 from the x values and 6 from the y values, and that would be:

W' (-6, 1)

X' (-1, -1)

Y' (-3, -6)

Z' (-8, -4)

For question 9 you would end up with:

X' (6, -5)

Y' (7, 1)

Z' (4, 0)

For question 10 you would end up with:

Q' (-1, 2)

R' (1, 7)

S' (-2, 6)

T' (-4, 1)

For question 11 you would end up with:

L' (4, 1)

M' (8, 5)

N' (6, 7)

P' (2, 3)

For question 12 you would end up with:

G' (6, -7)

H' (6, -4)

I' (1, -7)

Hope this is what you were looking for!

 

Step-by-step explanation:


4 0
3 years ago
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