Step by Step:
(z^2 -2z)(10z-20)
z(z-2)+10(z-2)
(z+10)(z-2)
Hope this helps.
Let
C-------> the length of a circumference
C=2*pi*r-----> equation 1
we know that
in this problem-----> <span>the circumference of the foundation is 4 times the radius, increased by 114 ft
</span>so
C=4*r+114------> equation 2
(1)=(2)
2*pi*r=4*r+114------> 2*pi*r-4*r=114-----> r*[2*pi-4]=114---> r=114/[2*pi-4]
r=114/[2*pi-4]-----> 50 ft
the answer is
r=50 ft
The area of the red piece of paper is A= 4(2*4)= 4*8= 32 in^2.
The area of the blue piece of paper is A= 3*7=21 in^2. You subtract 21 from 32 and the difference is 11. So 11in^2 is visible.
Well, the affect would be 3x less on the area of the square
Answer:
(6, 3)
Step-by-step explanation:
x=6 y=3
2(6) -3 =9
12 -3 = 9
