Answer for the above question is <u>option C</u>
<u>Step-by-step explanation:</u>
<u>Option C -</u> It's a quadrilateral but not a rhombus . As we know rhombus has congruent sides while its two angle can't be measured 120 degrees but in option C it seems two vertically opposite angles of to be 120 degrees. In rhombus opposite angles are same while adjacent angles are supplementary. All options except C are the rhombus of congruent sides.
Answer:
40% students play the saxophone.
Step-by-step explanation:
Given:
Total Number of students who play woodwind instrument = 45
Number of students who play saxophone = 18
We need to find the percent of students who play saxophone.
Solution:
Now we can say that;
To find the percent of students who play saxophone we will divide Number of students who play saxophone by Total Number of students who play woodwind instrument and the multiply by 100.
framing in equation form we get;
percent of students who play saxophone = 
Hence 40% students play the saxophone.
9514 1404 393
Answer:
The pool is being filled
Step-by-step explanation:
The function definition tells you ...
f(5) = the volume of water in the pool 5 minutes after they start
f(10) = the volume of water in the pool 10 minutes after they start
So, the inequality ...
f(5) < f(10)
means the volume of water in the pool 10 minutes after they start is greater than it is 5 minutes after they start. In short, <em>they are filling the pool</em>.
6x=-5y
-5y=6x
so the answer is y=-6/5x
Answer:
x=2.125
y=0
C=19.125
Step-by-step explanation:
To solve this problem we can use a graphical method, we start first noticing the restrictions
and
, which restricts the solution to be in the positive quadrant. Then we plot the first restriction
shown in purple, then we can plot the second one
shown in the second plot in green.
The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.
So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.