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2 years ago

Gail has $7,500 that she wants to put in a new savings account. She is

Mathematics

1 answer:

ElenaW [278]2 years ago

6 0

Easy answer, Neighborhood Bank. But to see how:

$7,500 * 0.015 (1.5%) = $112.50

$112.50 a day times 360 days = $40,500

$40,500 times 20 = $810,000.

$810k times 20 = $16,200,000. (16.2mil)

$112.50 times 20 = $2,250.

So..

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Mrs. kirby, 58, is a moderately active woman. she works in the garden almost daily, occasionally walks with her friends, and bab

uranmaximum [27]

Answer:

61,01%

Step-by-step explanation:

We must consider that her total energy intake is the addition of the energy given by the carbohydrates, fats and proteins she takes.

1g of carbohydrates contains 4kcal

1g of proteins contains 4kcal

1g of fat contains 9 kcal.

That is: 243 g of carbohidrates is equal to 972 kcal; 41g of fat is equal to 369 kcal and 63 g of proteins is equal to 252 kcal.

If we sum up all the calories she intakes in one day, the result is= 972kcal+369kcal+252kcal=1593kcal.

Now, we make a rule of 3: If 1593kcal is the 100% of the intake, then 972kcal = 972kcal*100%/1593kcal = 61,01%

5 0

3 years ago

11.3 x 3 = 28.25 please show the formula

Verizon [17]

65.98 because of it I have no clue how much you want me and you to get me some of my stuff I need you I know I have a good idea of that but I’m still in a little while

4 0

3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

3 years ago

I need help please !

Orlov [11]

It is A so you have it right

4 0

3 years ago

Read 2 more answers

30PTS TO ANYONE WHO CAN ANSWER WITH THIS PROBLEM

Anni [7]

Answer:

$y\tan{x°}$

Step-by-step explanation:

well, by using definition of tan of an angle

let the distance between Earth and shooting star is $d$ .

since $\frac{d}{y}=\tan{x°}$ ,

then $d=y\tan{x°}$

8 0

3 years ago